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densk [106]
3 years ago
9

What did you observe happening in the cups?

Chemistry
2 answers:
zhannawk [14.2K]3 years ago
6 0
I think it gets foggy in the cup i think but good luck!!
Leya [2.2K]3 years ago
5 0
A phase change will occur , it will first become blurry due to water vapour evaporating and cool down to tiny water droplets when coming in contact with the plastic cup ( hope im right , its been awhile! )
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What was a major accomplishment of the Apollo mission
denpristay [2]
Hi there!

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4 0
3 years ago
Can someone help out pls
Troyanec [42]

Answer:

1. Acids

2. Its molecular arrangement

3. Very acidic

4. Unsaturated

5. Apple juice

Explanation:

1. Acids have pH less than 7

2. Water molecules have a polar arrangement of the oxygen and hydrogen atoms—one side (hydrogen) has a positive electrical charge and the other side (oxygen) had a negative charge.3. Very acidic

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5. The lower the pH, the more hydrogen molecules.

4 0
2 years ago
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Types of osmosis...in 50 words​
ICE Princess25 [194]

<h3>Types of Osmosis</h3>

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6 0
3 years ago
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At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 165 minutes, her sample has decayed to 5.
Paul [167]
The half-life equation is written as:

An = Aoe^-kt

We use this equation for the solution. We do as follows:

5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes? 
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE


Find a formula for G(t) , the amount of goo remaining at time t.G(t)=? 

G(t) = 176e^-0.02t

How many grams of goo will remain after 50 minutes? 

G(t) = 176e^-0.02(50) = 64.75 g
6 0
3 years ago
the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig
Dmitrij [34]

Answer:

Faraday's constant will be smaller than it is supposed to be.

Explanation:

If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.

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