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2 years ago

Why does beethoven now spend all his time erasing music

Mathematics

1 answer:

schepotkina [342]2 years ago

3 0

He is decomposing :0

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Y=3(50)x

solmaris [256]

Answer:

y=3(50)×

y=3(50) 8

50×3=150

150×8=1,200

6 0

2 years ago

The data shows the weights of 2 groups of house cats in pounds.

lesantik [10]

I would say the answer is C

5 0

2 years ago

Any help would be great

Aloiza [94]

Answer:

3/4

Step-by-step explanation:

A ratio of the diameters is one diameter divided by the other so the miniDVD divided by the DVD = 9/12 or 3/4.

8 0

3 years ago

4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.

jeka57 [31]

Answer:

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

Step-by-step explanation:

as per question given data

√3 ≈ 1.732 050 8

to find out

sequence of five intervals

solution

as we have given that √3 value that is here

√3 ≈ 1.732 050 8 ........................1

when we find $2^{\sqrt{3} }$ ................2

put here √3 value in equation number 2

we get $2^{\sqrt{3} }$ that is 3.322

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

8 0

2 years ago

Calcula: +(-4)+(1/3)+(√7)=<br> me ayudan??????

dybincka [34]

Answer:

=−11/3 +√7

(Decimal: -1.020915)

7 0

2 years ago