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frozen [14]
3 years ago
11

What is the answer to this u(2u+5)-4(U+3)​

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

its 2u^2-4u+5u-12

Step-by-step explanation:

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A stack of 6 bricks is 2 feet high. How high is a stack of 20 bricks?
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60.

The question gives you the fact that 6 bricks is 2 feet high.

What do you do to get from 2 to 20?
You multiply by 10.

Since you multiplied one thing by 10, you must do it to the other side so it remains balanced.

2 ft x 10ft = 20ft

6 bricks x 10 bricks = 60 bricks
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What is the square root of 16
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3 years ago
Evaluate -5-15+4+15
defon

Answer:

-1

Step-by-step explanation:

-5-15+4+15

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The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th
ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

z=\frac{x-\mu}{\sigma}

z=\frac{38-38}{6}=\frac{0}{6}=0

Now we will find z-score corresponding to 56.

z=\frac{56-38}{6}=\frac{18}{6}=3

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is -3\sigma\text{ to }3\sigma.

We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.

We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

\frac{99.7\%}{2}=49.85\%

Therefore, approximately 49.85\% of lightbulb replacement requests numbering between 38 and 56.

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3 years ago
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