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sertanlavr [38]
4 years ago
11

(P L E A S E BE QUICK)

Mathematics
2 answers:
Lelechka [254]4 years ago
7 0
39% it is really 38.88888888 percent but you round it

4vir4ik [10]4 years ago
7 0

Answer:

The answer is 64%

Step-by-step explanation:

35/55 divided by 5=7/11

7/11= about 64%

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Split 18 into the ratio 1:2<br>​
Eva8 [605]

Answer:

6:12

Step-by-step explanation:

Add 1+2=3

18/3=6

6x1=6

6x2=12

Out it back in the ratio

6:12

8 0
3 years ago
I need help on number 1
Neko [114]

Answer:

Step-by-step explanation:

area of circle=πr^2

=3.14*5^2

=3.14*25

=78.5 ft^2

5 0
3 years ago
Which expression can be used to determine the length of segment AB?
Stells [14]

Answer:

you need to provide a picture friend

3 0
4 years ago
Read 2 more answers
There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am
Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

n = 479, \pi = \frac{130}{479} = 0.2714

Hence the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
Robin, who is self-employed, contributes $4500/year into a Keogh account. How much will he have in the account after 30 years if
pashok25 [27]

Answer:

The amount that would be in the account after 30 years is $368,353

Step-by-step explanation:

Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly

We proceed to use the formula below;

A = [P(1 + r)^t-1]/r

From the question;

P is the amount deposited yearly which is $4,500

r is the interest rate = 2.5% = 2.5/100 = 0.025

t is the number of years which is 30

Substituting these values into the equation, we have;

A = [4500(1 + 0.025)^30-1]/0.025

A = [4500(1.025)^29]/0.025

A = 368,353.3309607034

To the nearest whole dollars, this is;

$368,353

4 0
3 years ago
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