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3 years ago

What’s common denominators for 2/5 and 3/5

Mathematics

1 answer:

MrMuchimi3 years ago

6 0

Answer:

Step-by-step explanation:

The fractions already have a common denominator of 5

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give the length and width in whole inches of three different rectangles that each have an area of 48 in. squared

lozanna [386]

To find the length and width of 3 different rectangles that have an area of 48 square inches, you can use the factor pairs that result in 48.

The reason is that to find the area of a rectangle you multiply two dimensions.

2 in x 12 in
3 in x 8 in
4 in x 6 in

On all these either one could be the length and the other the width.

8 0

3 years ago

X - 5y = -20 y = ax + b

GuDViN [60]

Answer:

I Graphed It

Step-by-step explanation:

6 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), x

Y_Kistochka [10]

When the ball hit the ground, the height of the ball will be zero. So using the value of h(x) as zero in the given equation, we can find the time in which the ball will hit the ground.

$0=-(x-2)^{2}+16 \\ \\ 
(x-2)^{2}=16 \\ \\ 
x-2= \sqrt{16} \\ \\ 
x-2=4 \\ \\ 
x=6$

This means the ball will hit the ground 6 seconds after Amir threw it

6 0

3 years ago

Read 2 more answers

M + 5n = p solve for m

atroni [7]

-5n on both sides
M= -5n + p

8 0

3 years ago

Read 2 more answers