The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.
<h3>What are the results of the arithmetic evaluations?</h3>
The arithmetic operations above can be evaluated and simplified as follows;
(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.
(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.
(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.
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A) The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. You know the length of the gift shop, l = 20x + 24. You know the width, w = 36x - 20. Plug those expressions into the equation for area of a rectangle and multiply/foil:
The expression for the area of the gift shop is
.B) The equation for the perimeter of the gift shop is P = 2(l+w), where l = length and w = width. Plug your values for l and w into this equation:
The expression for the perimeter of the gift shop is 112x + 8
C) Since you know the perimeter is going to be 176 ft, that means P = 176. Plug that into the equation you found in part B, P = 112x + 8, and solve for x.

Once you solve for x, you can plug x into your equations for width and length to find the dimensions. x = 1.5, so:
1) L<span>ength = 20x+24 feet
</span>
Length = 20(1.5) + 24 feet =
54 feet
2) Width = <span>36x-20 feet
Width = 36(1.5)-20 feet =
34 feet
Your dimensions are 54 feet (length) by 34 feet (width).</span>
5/2 * 6 = 15
h/6 * 6 = h
so
h = 15
The school is 15ft tall
I assume you mean
2 tonnes of sand
at £75.00 per tonne
20 bags of cement
at £6.70 per bag
350 bricks at 45p each
If so, then
2 tonnes of sand
at £75.00 per tonne = 2 * £75.00 = £150.00
20 bags of cement
at £6.70 per bag = 20 * £6.70 = £134.00
350 bricks at 45p each = 350 * £0.45 = £157.50
Add the three amounts
£150.00 + £134.00 + £157.50 = £441.50
Answer: 441.50