Answer:
74.55Hp
Explanation:
Hello! To solve this problem we must do the following 3 steps.
1. Find the ideal power using the equation to find the power W = mgV
W=mgV
where
M=mass of elevator=1700kg
g=gravity=9.81m/S^2
V=speed=3m/S
W=(1700kg)(9.81m/S^2)(3m/s)=50031W
2.
Now as the problem indicates that 10% of energy is lost in the mechanical system, we divide the power found in the previous step by 90%
3.
finally we convert units from W to hp.
the minimum output power rating in HP of the motor that meets the requirement is 74.55Hp