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IRISSAK [1]
3 years ago
12

a body of mass 2kg is released from rest on a smooth plane at an angle of 60 degree to the horizontal.calculate the acceleration

of the body down the plane (g=10ms-2​
Physics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

8.66m/s2

Explanation:

from newton second laws F=ma

the force down the plane is the component force along the plane which is mgsin₩ so there fore

a= gsin₩ = 10sin60= 8.66m/s2

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A small first-aid kit is dropped by a rock climber who is descending steadily at 1.9 m/s. After 2.4 s, what is the velocity of t
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v=-21.65 m/s

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weqwewe [10]

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2. The linear acceleration is equal to 2.45m/s^2

3.the time it takes the ball to begin rolling = 0.98s

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B=2.74\times 10^{-10}\ T

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It is given that,

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So, the magnetic vector at point P at that instant is 2.74\times 10^{-10}\ T.

3 0
3 years ago
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