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Svetradugi [14.3K]
3 years ago
13

Hufflepuff and Ravenclaw are having their annual tug of war contest. Each team can have 20 students. What is the most important

variable to have an edge up in the competition?
Physics
2 answers:
Leviafan [203]3 years ago
6 0

    I'm sorry if my answer is too late but they didn't provide the letter S as a variable to represent the students. If that were the answer they would have specifically provided that information in the question. I'm a student of K12 as well so I can confirm that the answer is

B)The overall mass of the team.

Have a nice day!

Troyanec [42]3 years ago
3 0

It should be S since S stands for students. Giving the team with more members the upper hand. Hope this helps.

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It is an employer's responsibility to provide training for special equipment. true false
Naddik [55]

Answer:

True I hope you like it

Give me a brainliest answer

6 0
3 years ago
A force vector F1 points due east and has a magnitude of 200 Newtons, A second force F2 is added to F1. The resultant of the two
Andrew [12]
A force vector F1 points due east and has a magnitude of 200 Newtons, A second force F2 is added to F1. The resultant of the two vectors has a magnitude of 400 newtons and points along the due east/west line. Find the magnitude and direction of F2. Note that there are two answers. <span>The given values are
F1 = 200 N</span> F2 =? Total = 400 N

Solution: F1 + F2 = T 200 N + F2 = 400N
F2 = 400 - 200
F2 = 200 N



4 0
3 years ago
Current evidence suggests that many massive jovian planets orbit at very close orbital distances to their stars. How do we think
ivanzaharov [21]

Answer:

In the Solar system, the Jovian planets are farther from the Sun. Majority of the extrasolar Jovian planets are closer to their stars. These are known as "Hot Jupiters". From the studies, the reason for the existence of massive Jovian planets to be closer to their star is found to be the gravitational interaction of these planets with other massive planets which pushes them closer to their stars. These planets are formed beyond the frost line initially but later on migrate inwards.

4 0
3 years ago
2. A student drives 7.8-km trip to school and averages a speed of
Alekssandra [29.7K]

Answer:

<em>The total time is: t=451.22 sec</em>

<em>The average speed is: V=34.57 m/s</em>

Explanation:

<u>Average speed</u>

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

\displaystyle V=\frac{x}{t}

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec

The total time is:

t=239.26\ sec+211.96\ sec=451.22\ sec

\boxed{t=451.22\ sec}

The average speed is:

\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s

\boxed{\displaystyle V=34.57\ m/s}

6 0
3 years ago
The ground state energy of an electron in a one-dimensional trap with zero potential energy in the interior and infinite potenti
ElenaW [278]

Answer:

0.5 eV

Explanation:

E_1 = Initial potential energy = 2\ eV

E_2 = Final potential energy

L_1 = Initial width

L_2 = Final width = 2L_1

Energy of an electron in a one-dimensional trap is given by

E=\dfrac{n^2h^2}{8mL^2}

From the equation we get

E\propto \dfrac{1}{L^2}

So,

\dfrac{E_1}{E_2}=\dfrac{L_2^2}{L_1^2}\\\Rightarrow E_2=\dfrac{E_1L_1^2}{L_2^2}\\\Rightarrow E_2=\dfrac{2L_1^2}{4L_1^2}\\\Rightarrow E_2=0.5\ eV

The ground state energy will be 0.5 eV

6 0
3 years ago
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