Answer with Explanation:
We are given that
Mass of box=35 kg
Coefficient of static friction between box and truck bed=0.202
Acceleration due to gravity=
a.We have to find the force by which the box accelerates forward.
Force by which box accelerates=
Force by which box accelerates=
b.We have to find the maximum acceleration can the truck have before the box slides.
Force =friction force


Hence, the truck can have maximum acceleration before the box slide=
Answer:
Pressure,
Explanation:
It is given that,
Mass of the woman, m = 55 kg
Diameter of the circular cross section, d = 6 mm
Radius, r = 3 mm = 0.003 m
Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :




So, the pressure exerted on the floor is
. Hence, this is the required solution.
Answer:
Approximately
, assuming that the acceleration of this ball is constant during the descent.
Explanation:
Assume that the acceleration of this ball,
, is constant during the entire descent.
Let
denote the displacement of this ball and let
denote the duration of the descent. The SUVAT equation
would apply.
Rearrange this equation to find an expression for the acceleration,
, of this ball:
.
Note that
and
in this question. Thus:
.
Let
denote the mass of this ball. By Newton's Second Law of Motion, if the acceleration of this ball is
, the net external force on this ball would be
.
Since
and
, the net external force on this ball would be:
.
Answer:
Explanation: Here we have given a direct equation . There for no need to worry .
P = I²×R
P = (12)² ×100
P = 14400W = 14.4 kW
For second one
P = I² ×R
200 = I²×150
I = √200/150
I = 1.15 A
Answer:
Time and velocity
Explanation:
The time taken for the velocity to double is very important to find the amount of acceleration the car acquires.
Acceleration is the rate of change of velocity with time.
Acceleration =
v is the initial velocity
u is the final velocity
t is the time taken
So, the velocity and time is needed to calculate the value of the acceleration the car undergoes.