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BlackZzzverrR [31]
3 years ago
12

A boy 1m tall looks at the swimming pool, which appears to be 75 cm deep, according to the people around him. He finds himself a

lmost completely submerged in water when he steps into the water. Was he tricked? How did it happen?
Physics
1 answer:
Leto [7]3 years ago
4 0
When you look vertically downwards into a swimming pool full of water the bottom of the pool seems closer to you than it really is. The apparent depth at this point can be worked out using the formula:

Apparent depth = Real depth/Refractive index of water

However as you look towards the end of the pool the bottom seems to curve upwards – we are thinking about a pool of constant depth to start with.


If the depth of the pool really does change then the situation becomes more complex and you would need to allow for that when drawing the diagram
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While a roofer is working on a roof that slants at 39.0 degrees above the horizontal, he accidentally nudges his 88.0 N toolbox,
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Answer:

V= 6.974 m/s

Explanation:

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Fnet=37.4 N

acceleration of tool box down roof

a = 37.4(9.81)/88.0

a= 4.169 m/s²

d = 4.90 m

t = √2d/a

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t= 1.662 s

V = at

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3 years ago
In a second order lever system the force ratio is 2.5, the load is at the distance of 0.5m from the fulcrum find distance of eff
Fynjy0 [20]

Answer:

1.25 m

Explanation:

From the question given above, the following data were obtained:

Force ratio = 2.5

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Force ratio = Distance of effort / Distance of load

2.5 = Distance of effort / 0.5

Cross multiply

Distance of effort = 2.5 × 0.5

Distance of effort = 1.25 m

Therefore, the distance of the effort from the fulcrum is 1.25 m

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