Answer:
options A and C
Explanation:
Since, the spheres are of same size and rotational speed of the sphere are not dependent on their masses. So, both the sphere will reach the bottom of the at the same time with the same speed. But their kinetic energies are different.
So, options A and C are correct.
Answer:
4.186 m/s^2
Explanation:
First, convert km/hr to m/s:
(75 km/hr)(1000m/1km)(1hr/60min)(1min/60s) = 20.83 m/s
Then, divide 20.93 m/s by 5.0s
(20.93 m/s) / (5.0s) = 4.186 m/s^2
Answer:
salt water, air and vinegar are homogeneous solutions.
Explanation:
A solution which consists of particles of same proportion is known as a homogeneous solution. Whereas a solution which consists of particles of different proportion is known as a heterogeneous solution.
Salt and water are homogeneous solutions as salt completely disperses in water and forms a clear solution as the particles of salt and water are in proportion.
Air is composed of different gases like nitrogen, oxygen etc are all mixed in fixed ratio. Therefore, air is a homogeneous mixture.
Sand and water are heterogeneous solution as the ration of mixing is different and more over sand particles can be separated from water. Thus, it is not a homogeneous mixture.
Vinegar is also a homogeneous solution as it is composed of acetic acid and water which are mixed in fixed proportion.
Cement is a heterogeneous mixture as it is composed of a number of different substances mixed in different proportions.
Thus, we can conclude that salt water, air and vinegar are homogeneous solutions.
Answer:
The direction of the displacement is in North-West.
Explanation:
Resultant displacement D is
Here the direction is

Then the direction is
North-west.
Answer:
Explanation:
Let the charge on proton be q .
energy gain by proton in a field having potential difference of V₀
= V₀ q
Due to gain of energy , its kinetic energy becomes 1/2 m v₀²
where m is mass and v₀ is velocity of proton
V₀ q = 1/2 m v₀²
In the second case , gain of energy in electrical field
= 2 V₀q , if v be the velocity gained in the second case
2 V₀q = 1/2 m v²
1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²
mv² = 2 m v₀²
v = √2 v₀