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PolarNik [594]
3 years ago
13

The compound dimethylamine, (CH3)2NH, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

ium that occurs in an aqueous solution of dimethylamine:
Chemistry
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

K_b=\frac {[(CH_3)_2{NH_2}^+][OH^-]}{[(CH_3)_2NH]}

Explanation:

Kb is base dissociation constant which is measure of the dissociation of a base into component ions in the water.

The base, (CH₃)₂NH dissociates in water as:

(CH₃)₂NH (aq) + H₂O (l)  ⇄ (CH₃)₂NH₂⁺ (aq) + OH⁻ (aq)

The expression for Kb is:

K_b=\frac {[(CH_3)_2{NH_2}^+][OH^-]}{[(CH_3)_2NH]}

Water is present in large amounts and is not written in the expression for Kb.

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Answer:

ΔS = +541.3Jmol⁻¹K⁻¹

Explanation:

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To find the entropy change of the reaction, we first write a balanced reaction equation:

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To calculate the entropy change of the reaction we simply use the equation below:

      ΔS = ∑S_{products} - ∑S_{reactants}

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     ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1

                          ΔS = +541.3Jmol⁻¹K⁻¹

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