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PolarNik [594]
3 years ago
13

The compound dimethylamine, (CH3)2NH, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

ium that occurs in an aqueous solution of dimethylamine:
Chemistry
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

K_b=\frac {[(CH_3)_2{NH_2}^+][OH^-]}{[(CH_3)_2NH]}

Explanation:

Kb is base dissociation constant which is measure of the dissociation of a base into component ions in the water.

The base, (CH₃)₂NH dissociates in water as:

(CH₃)₂NH (aq) + H₂O (l)  ⇄ (CH₃)₂NH₂⁺ (aq) + OH⁻ (aq)

The expression for Kb is:

K_b=\frac {[(CH_3)_2{NH_2}^+][OH^-]}{[(CH_3)_2NH]}

Water is present in large amounts and is not written in the expression for Kb.

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8 0
3 years ago
Is tap water a compound, a homogenous mixture, or a heterogeneous mixture?
goldenfox [79]
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4 0
4 years ago
what is the temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3L at 55 degrees Celsius and 7
Rus_ich [418]

Answer:

3 °C

Explanation:

The pressure is constant, so this looks like a case where we can use Charles’ Law:

\frac{ V_{1} }{T_{1}} = \frac{V_{2} }{T_{2}}  

Invert both sides of the equation.

\frac{T_{1} }{V_{1}} = \frac{T_{2} }{V_{2}}

Multiply both sides by <em>V</em>₂

T_{2} = T_{1} \times \frac{V_{2} }{ V_{1} }

<em>V</em>₁ = 13.3 L; <em>T</em>₁ = (55 + 273.15) K = 328.15 K

<em>V</em>₂ = 11.2 L; <em>T</em>₂ = ?

T_{2} = \text{328.15 K} \times \frac{\text{11.2 L} }{\text{13.3 L}} = \text{276 K} = 3 ^{\circ}\text{C}

8 0
3 years ago
Which acid was most likely used for the titration graph below.
sleet_krkn [62]
Hci acid its high preety cool
6 0
4 years ago
Read 2 more answers
Look into the picture for the question.​
ira [324]

Answer:

Option D. 1092K

Explanation:

T1 = 273K

V1 = V

P1 = P

V2 = 2V( i.e double of original volume)

P2 = 2P (i.e double of original pressure)

T2 =?

P1V1/T1 = P2V2/T2

PV/273 = 2P x 2V / T2

Cross multiply to express in linear form

PV x T2 = 273 x 2P x 2V

Divide both side by PV

T2 = (273 x 2P x 2V) / PV

T2 = 273 x 2 x 2

T2 = 1092K

3 0
4 years ago
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