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Misha Larkins [42]
3 years ago
12

How does a sample of helium at 15 degree Celsius compare to a sample of helium at 215 K?

Chemistry
2 answers:
Nadusha1986 [10]3 years ago
5 0
The answer is A.
215K is equivalent to -58.15 °C and temperature corresponds with the average kinetic energy.
So the 15°C has a higher energy level than 215K.
lara [203]3 years ago
5 0

Answer:

A) The helium at 15 degrees Celsius has a higher average kinetic energy that the sample at 215 K.

Explanation:

First, we must compare the two different temperatures in the same units. To convert Celsius into kelvin we must add it 273, so

K = °C + 273 = 15°C + 273 = 288K

And 288K > 215 K then 15°C > 215K

The increase of temperature in a gas sample causes an increase in the atom’s movement, i.e. the atoms move faster when they are heated and, for this reason, the kinetic energy of the system increases.

As helium at 15°C (288K) implies that has a higher temperature than helium at 215K, then its kinetic energy will be higher too.

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An electric current can be measured with a device called?
worty [1.4K]

Answer: Ammeter

Explanation:

7 0
3 years ago
Identify the number of protons and electrons
vredina [299]
Fluorine has 9 protons and 9 electrons
Iodine has 53 protons and 53 electrons
6 0
3 years ago
Solid iron (III) oxide reacts with hydrogen gas to form iron and water. How many grams of iron are produced when 440.23 grams of
Nookie1986 [14]

When 440.23 grams of iron(III) oxide are reacted with hydrogen gas, the amount of iron produced will be 307.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

Fe_2O_3 + 3H_2 --- > 2Fe + 3H_2O

The mole ratio of iron(III) oxide to produced iron is 1:2.

Mole of 440.23 iron(III) oxide = 440.23/159.69 = 2.76 moles

Equivalent mole of produced iron = 2.76 x 2 = 5.52 moles

Mass of 5.52 moles of iron = 5.52 x 55.8 = 307.66 grams

More on stoichiometric calculations can be found here; brainly.com/question/27287858

#SPJ1

4 0
2 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 7.80 moles of magnesium perchlorate, Mg(ClO4)2.
Dmitry [639]
 The number of moles of moles of  Magnesium,chlorine and oxygen atoms in 7.80 moles of Mg(ClO4)2 is calculated as below

find the total number of each atom in Mg(ClO4)2

that is mg = 1 atom
        Cl =  1x2 = 2 atoms
        O  = 4  x2 = 8 atoms

then multiply 7.80 moles with total number of each atom , to get the number moles of each atom
that is

Mg = 7.80 x1= 7.80  moles
cl =   7.80  x2=15.6  moles
O =  7.80 x8= 62.4 moles

5 0
3 years ago
Collected data consists of:
san4es73 [151]

The number of moles of the magnesium (mg) is 0.00067 mol.

The number of moles of hydrogen gas is 0.0008 mol.

The volume of 1 more hydrogen gas (mL) at STP is 22.4 L.

<h3>Number of moles of the magnesium (mg)</h3>

The number of moles of the magnesium (mg) is calculated as follows;

number of moles = reacting mass / molar mass

molar mass of magnesium (mg) = 24 g/mol

number of moles = 0.016 g / 24 g/mol = 0.00067 mol.

<h3>Number of moles of hydrogen gas</h3>

PV = nRT

n = PV/RT

Apply Boyle's law to determine the change in volume.

P1V1 = P2V2

V2 = (P1V1)/P2

V2 = (101.39 x 146)/(116.54)

V2 = 127.02 mL

Now determine the number of moles using the following value of ideal constant.

R = 8.314 LkPa/mol.K

n = (15.15 kPa x 0.127 L)/(8.314 x 290.95)

n = 0.0008

<h3>Volume of 1 mole of hydrogen gas at STP</h3>

V = nRT/P

V = (1 x 8.314 x 273) / (101.325)

V = 22.4 L

Learn more about number of moles here: brainly.com/question/13314627

#SPJ1

7 0
2 years ago
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