Answer:
46.40 g.
Explanation:
- It is a stichiometric problem.
- The balanced equation of the reaction: 4K + O₂ → 2K₂O.
- It is clear that 4.0 moles of K reacts with 1.0 mole of oxygen produces 2.0 moles of K₂O.
- We should convert the mass of K (38.5 g) into moles using the relation:
<em>n = mass / molar mass,</em>
n = (38.5 g) / (39.098 g/mol) = 0.985 mole.
<em>Using cross multiplication:</em>
4.0 moles of K produces → 2.0 moles of K₂O, from the stichiometry.
0.985 mole of K produces → ??? moles of K₂O.
∴ The number of moles of K₂O produced = (0.985 mole) (2.0 mole) / (4.0 mole) = 0.4925 mole ≅ 0.5 mole.
- Now, we can get the mass of K₂O:
∴ mass = n x molar mass = (0.5 mole) (94.2 g/mol) = 46.40 g.
It either forms a base or an acid...I think that's the answer you're looking for
Answer:
Explanation:
Hello there!
In this case, it is possible to propose an energy balance in order to illustrate how the heat released by the reaction is absorbed by the water:
Thus, since the heat released by the reaction is -112 kJ (-112000 J), it is possible to define the hear absorbed by the water in terms of mass, specific heat and temperature change:
In such a way, it is possible to define the final temperature as shown below:
Best regards!
Complete dominance.... Hope this helps
Answer:
1.38 M
Explanation:
Need to use the Molarity equation M=n/L
23.5g/ 17.031g/mol NH3 = 1.38 moles
1.38 moles/ 1.0 L = 1.38 M
