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Zigmanuir [339]
2 years ago
6

2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)

Chemistry
1 answer:
balandron [24]2 years ago
3 0

The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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Answer:

in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution. (option C).

Explanation:

In a reaction where NaOH is added to H2O.

NaOH is considered a strong base, this means that in an aqueous solution ( in water) it's  able to completely disassociate in ions.

There will not remain any NaOH in the solution. This means option D is not correct.

The ions in which NaOH will disassociate are : NaOH → Na+ + OH-

These ions we will find in the solution.

Not only Na+ because NaOH is a strong base, so there will be a lot of OH- ions as well in solution.

This means in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution.

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777dan777 [17]

Answer:

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