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Zigmanuir [339]
2 years ago
6

2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)

Chemistry
1 answer:
balandron [24]2 years ago
3 0

The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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To prepare 1.00 L of 14g BaCl2, what Molarity would it be?​
nikklg [1K]

Answer:

0.067 M  

Explanation:

Given data:

Volume of solution = 1.00 L

Mass of BaCl₂ = 14 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles first.

Number of moles = mass/ molar mass

Number of moles = 14 g/ 208.23 g/mol

Number of moles = 0.067 mol

Now we will calculate the molarity.

Molarity = 0.067 mol / 1.00 L

Molarity  = 0.067 M    ( mol/L=M)

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What amount of heat is removed to lower the temperature of 80 grams of water from 75º C to 45º C? The specific heat of liquid wa
Sindrei [870]

Answer:The correct answer option A.

Explanation:

Q= m\times c\times \Delta T

Q= heat removed from the water

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c = heat capacity of water= 4.18 J/g°C      

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