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Andrews [41]
3 years ago
6

Which would best help will give brainlist first 1

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
6 0
Letter c. A hand lens
Because it magnifies the animal making it look bigger for the students to easily see and identify it.

Hope this explanation is helpful enough and don’t forget the brainleast :)
son4ous [18]3 years ago
3 0
It would definitely be hand lense
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The variable that a scientist changes when conducting an experiment is called the _____variable.
Flauer [41]
He variable that a scientist changes when conducting an experiment is called the manipulated variable
6 0
3 years ago
Read 2 more answers
What is the wavenumber of the radiation emitted when a hydrogen
LUCKY_DIMON [66]

Answer: Wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

where,

E = energy of the radiation = 1.634\times 10^{-18}J

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of radiation = ?

Putting values in above equation, we get:

1.634\times 10^{-18}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}\\\\\lambda=12.16\times 10^{-8}m

\bar {\nu}=\frac{1}{\lambda}=\frac{1}{12.16\times 10^{-8}}=0.08\times 10^{8}m^{-1}

Thus wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

8 0
3 years ago
Cobalt-60 and iodine-131 are radioactive isotopes that are used in
svlad2 [7]
Cobalt 60-Used to treat certain types of cancer.
Iodine-131-Used to monitor and treat goiter and other thyroid problems.It is also used to treat liver and brain tumor
Mark me as the Brainliest❤️❤️✌✌
8 0
3 years ago
Plsssss give me answer<br>​
34kurt

Explanation:

Medieval number one. There you havt it.

4 0
1 year ago
Determine the oxidation number for nitrogenin
iris [78.8K]

Answer:

1(a) N = 3

(b) N = 0

(c) N = 5

(d) N = -2

(2) Molecular formula for benzene is C6H6

Explanation:

1(a) N02 1-

N + (2×-2) = -1

N-4 = -1

N = -1+4 = 3

(b) N2

2(N) = 0

N = 0/2 = 0

(c) NO2Cl

N + ( 2×-2) + (-1) = 0

N - 4 - 1 = 0

N - 5 = 0

N = 0+5 = 5

(d) N2H4

2(N) + (4×1) = 0

2N + 4 = 0

2N = 0 - 4 = -4

N = -4/2 = -2

(2) Molcular mass of benzene = 78g/mole = (6×12g of carbon) + (6×1g of hydrogen) = 72+6 = 78g/mole

Therefore, molecular formula for benzene is C6H6

7 0
3 years ago
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