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3 years ago

8

How to solve this: (x-7x)+(3x-28)

1 answer:

klasskru [66]3 years ago

4 0

Answer:

Step-by-step explanation:

(x-7x)+(3x-28) = x - 7x + 3x -28

= -3x -28

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A gallon of gasoline cost 2.96. Your car has a 25 gallon gas tank and can travel 28.8 miles on each gallon of gasoline. How much

geniusboy [140]

<h2>Greetings!</h2>

Answer:

It would cost 47.36

Step-by-step explanation:

First, you need to find out how many gallons are needed to fill the tank. To do this, simply multiply 25 by the fraction that is how much is already in there:

25 x $\frac{3}{8}$ = 9.375

So that means that there is 9.375 gallons already in the tank. To find the amount needed to fill the tank:

25 - 9.375 = 15.625

So 15.625 gallons are needed, rounded up to 16 gallons because you cannot get a decimal value of gallons.

That means that 16 x the price = the amount to fill the tank:

16 x 2.96 = 47.36

So it would cost 47.36 to fill the tank!

<h2>Hope this helps!</h2>

4 0

4 years ago

Please help meeeee it’s actually super easy

rewona [7]

The area for that shape should be 28 because 20+8=28! Hope this helps.

4 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

3 years ago

Which linear function has the greater rate of change Y= 8x+ 3

Ad libitum [116K]

17 bc I did it trust me pls

6 0

3 years ago

Matthew's dad hired him to paint 6 wooden patio chairs for $125. It takes him 9 hours to paint all of the chairs. If it takes th

frozen [14]

Given:

Matthew's dad hired him to paint 6 wooden patio chairs for $125.

Time taken by him to paint all of the chairs = 9 hours.

It takes the same amount of time to paint each chair.

To find:

The fraction of an hour does it take Matthew to paint one chair

Solution:

Total time = 9 hours

Total number of chairs = 6

Now, time taken by Matthew to paint one chair is

$\dfrac{\text{Total time}}{\text{Total number of chairs}}=\dfrac{9}{6}$

$\dfrac{\text{Total time}}{\text{Total number of chairs}}=\dfrac{3}{2}$

Therefore, Mattew takes $\dfrac{3}{2}$ of an hour to paint one chair.

Thinking with a model: On dividing the total time by total number of chairs we get time taken by Mattew (in hours) to paint one chair. So, the result represents the fraction of an hour taken by Matthew to paint one chair.

8 0

3 years ago