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VashaNatasha [74]
3 years ago
7

A snail going full speed was taking 1/5 of a minute to move 1/2 of a centimeter. At this rate, how long would it take the snail

to travel a centimeter?
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0
24 seconds I think. What I did was:
1. Divide 60 by 5 to get what 1/5 of a minute is
2. That would be 0.5 cm in 12 seconds
3. To go from 0.5 cm to 1 cm we multiply by two
4. To keep it balanced we also multiply the time: 12*2= 24 seconds

So it would take the snail 24 seconds to move a centimeter.
If I'm wrong I apologize and I accept any corrections
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An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the
MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}=  1.45

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}=  3.59

6 0
3 years ago
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