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kicyunya [14]
3 years ago
8

Which of the following types of lithospheric crusts collide to produce large mountains such as the Himalayan mountains?

Physics
1 answer:
dlinn [17]3 years ago
7 0
A) Continental crust converging with oceanic crust
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HELP ASAP!!! The gravitational pull of the Moon is much less than the
katovenus [111]

Answer:

I'm pretty sure its B and C

Explanation:

B bc the weight is gravitational pull x mass so when the object has same mass the weight is smaller on moon

C bc mass is the same - you can't change it

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3 years ago
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A 14.8-g piece of Styrofoam carries a net charge of -0.742 µC and is suspended in equilibrium above the center of a large, horiz
MAXImum [283]
Base on your question where a 14.8g of piece of Styrofoam carries a net charge of -0.742C and is suspended in equilibrium above the center of a large, horizontal sheet of plastic so the ask of the problem is to calculate  the charge per unit area on the plastic sheet. The answer would be 21.96
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3 years ago
al aplicar una fuerza de 2 N sobre un muelle este se alarga 4cm.¿cuanto se alargara si la fuerza es el triple?¿que fuerza tendri
3241004551 [841]

1) 12 cm

2) 3 N

Explanation:

1)

The relationship between force and elongation in a spring is given by Hooke's law:

F=kx

where

F is the force applied

k is the spring constant

x is the elongation

For the spring in this problem, at the beginning we have:

F=2 N

x=4 cm

So the spring constant is

k=\frac{F}{x}=\frac{2N}{4 cm}=0.5 N/cm

Later, the force is tripled, so the new force is

F'=3F=3(2)=6 N

Therefore, the new elongation is

x'=\frac{F'}{k}=\frac{6}{0.5}=12 cm

2)

In this second problem, we know that the elongation of the spring now is

x=6 cm

From part a), we know that the spring constant is

k=0.5 N/cm

Therefore, we can use the following equation to find the force:

F=kx

And substituting k and x, we find:

F=(0.5)(6)=3 N

So, the force to produce an elongation of 6 cm must be 3 N.

6 0
3 years ago
In a "Rotor-ride" at a carnival, people rotate in a vertical cylindrically walled "room." If the room radius is 5.5 m, and the r
Crank

Answer:

0.181

Explanation:

We can convert the 0.5 rps into standard angular velocity unit rad/s knowing that each revolution is 2π:

ω = 0.5 rps = 0.5*2π = 3.14 rad/s

From here we can calculate the centripetal acceleration

a_c = \omega^2r = 3.14^2*5.5 = 54.3 m/s^2

Using Newton 2nd law we can calculate the centripetal force that pressing on the rider, as well as the reactive normal force:

F = N = a_cm = 54.3 m

Also the friction force and friction acceleration

F_f = N\mu = 54.3 m \mu N

a_f = F_f / m = 54.3 \mu

For the rider to not slide down, friction acceleration must win over gravitational acceleration g = 9.81 m/s2:

g = a_f = 54.3 \mu

9.81 = 54.3 \mu

\mu = 9.81 / 54.3 = 0.181

6 0
3 years ago
Un leopardo recorre 12.000 yardas, el tigre recorre 1.096.800 centímetros y un puma recorre 10,968 kilómetros. ¿Cuál de los tres
Maksim231197 [3]

El leopardo hizo el mayor recorrido.

7 0
3 years ago
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