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3 years ago

While traveling along a highway, a driver slows from 27 m/s to 13 m/s in 11 seconds. What is the automobile’s acceleration?

Physics

1 answer:

Travka [436]3 years ago

4 0

Answer:

$a=-1.27\ m/s^2$

Explanation:

Given that,

The initial speed of a driver, u = 27 m/s

Final speed of the driver, v = 13 m/s

Time, t = 11 s

We need to find the automobile's acceleration. We know that the acceleration of an object is equal to the change in speed divided by time taken.

$a=\dfrac{13-27}{11}\\\\a=-1.27\ m/s^2$

So, the magnitude of automobile's acceleration is $1.27\ m/s^2$ .

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A 2100 g block is pushed by an external force against a spring (with a 22 N/cm spring constant) until the spring is compressed b

Vilka [71]

Answer:

6.5e-4 m

Explanation:

We need to solve this question using law of conservation of energy

Energy at the bottom of the incline= energy at the point where the block will stop

Therefore, Energy at the bottom of the incline consists of the potential energy stored in spring and gravitational potential energy= $\frac{1}{2} kx^{2} +PE1$

Energy at the point where the block will stop consists of only gravitational potential energy= $PE2$

Hence from Energy at the bottom of the incline= energy at the point where the block will stop

⇒ $\frac{1}{2} kx^{2} +PE1=PE2$

⇒ $PE2-PE1=\frac{1}{2} kx^{2}$

Also $PE2-PE2=mgh$

where $m$ is the mass of block

$g$ is acceleration due to gravity=9.8 m/s

$h$ is the difference in height between two positions

⇒ $mgh=\frac{1}{2} kx^{2}$

Given m=2100kg

k=22N/cm=2200N/m

x=11cm=0.11 m

∴ $2100*9.8*h=\frac{1}{2}*2200*0.11^{2}$

⇒ $20580*h=13.31$

⇒ $h=\frac{13.31}{20580}$

⇒h=0.0006467m= $6.5e-4$

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4 years ago

A block slides on a table pulled by a string attached to a hanging weight. In case 1 the block slides without friction and in ca

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The tension in the string with friction would be the biggest because of the involvement of the force of gravity. This would result in that the friction force that is acting on the system. There is no friction in the frictionless system, and only the force of gravity is relevant.

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3 years ago

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A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret

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f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

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f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

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4 years ago

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Which of the following is not the result of nuclear decay.

svlad2 [7]

Answer:it’s c

Explanation:

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3 years ago

A crate filled with delicious junk food rests on a horizontal floor. Only gravity and the support force of the floor act on it,

stealth61 [152]

The words "... as shown ..." tell us that there's a picture that goes along
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3 years ago