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Inga [223]
3 years ago
14

A 97 kg man lying on a surface of negligible friction shoves a 62 g stone away from himself, giving it a speed of 2.6 m/s. What

speed does the man acquire as a result?
Physics
1 answer:
tangare [24]3 years ago
3 0

Answer:

man will move in opposite direction with speed

v_1 = 1.66 \times 10^{-3} m/s

Explanation:

As we know that man is lying on the friction-less surface

so here net force along the surface is zero

so if we take man + stone as a system then net change in momentum of this system will become zero

so here we have

P_i = P_f

0 = m_1v_1 + m_2v_2

here we have

0 = (97)v_1 + 0.062(2.6)

v_1 = -\frac{0.1612}{97}

v_1 = -1.66 \times 10^{-3} m/s

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Q= ΔU +W

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