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Rufina [12.5K]
4 years ago
14

which of these waves requires a medium to travel through light wave electromagnetic waves sound wave microwave

Physics
2 answers:
natita [175]4 years ago
9 0

Answer:

hello! the answer is c sound wave

Explanation:

i took the test ;)

navik [9.2K]4 years ago
7 0
Sound waves require a medium to travel through. :D 
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The most abundant element in earth's continental crust (by weight) is____?
sashaice [31]
The answer is A. Oxygen
8 0
3 years ago
Read 2 more answers
Two neutral metal spheres on wood stands are touching. A negatively charged rod is held directly above the top of the left spher
Paha777 [63]

Answer:

The right sphere is negatively charged, the left sphere is charged positively.

Explanation:

When a negatively charged rod is held above the top of left sphere, the rod will attract positive charges and repel negative charges. As the sphere are initially touching each other so positive charges from the both spheres will moves toward the rod. When we separate the spheres positive charges from right sphere have already moved toward the rod i.e. left sphere, creating a deficiency of positive charges in the right sphere and excessiveness of positive charges in left sphere , hence the right sphere will remain negatively charged and left sphere will remain positively charged.

4 0
4 years ago
A car is travelling at a constant speed of 26.5 m/s. Its tires have a radius of 72 cm. If the car slows down at a constant rate
maksim [4K]

Answer:

Magnitude of angular acceleration = -3.95 rad/s²

Explanation:

Angular acceleration is the ratio of linear acceleration and radius.

That is

        \texttt{Angular acceleration}=\frac{\texttt{Linear acceleration}}{\texttt{Radius}}\\\\\alpha =\frac{a}{r}

Radius = 72 cm = 0.72 m

Linear acceleration is rate of change of velocity.

a=\frac{11.7-26.5}{5.2}=-2.85m/s^2

Angular acceleration

        \alpha =\frac{a}{r}=\frac{-2.85}{0.72}=-3.95rad/s^2

Angular acceleration = -3.95 rad/s²  

Magnitude =  3.95 rad/s²     

4 0
3 years ago
Someone please help??
stira [4]
The efficancy is .375
5 0
3 years ago
It takes 6 sec for a stone to fall the the bottom of a mineshaft. calculate the
Stels [109]
Ok so this is simple projectile motion problem.

if we have an object falling in free fall it is subject to gravity of -9.80m/s^2

so it says it takes 6 sec to fall and we know initial velocity was zero so we know that h=vt+1/2gt^2 so we get h=0+1/2*9.80*6^2 = 176.4m 

so solving for final speed we get KE=PE = 1/2mv^2=mgh = 1/2v^2=gh so 
v=sqrt(2*g*h) = sqrt(2*9.8*176.4m) = 58.8m/s final speed when it hits the ground


hope this helps you! Thanks!!

8 0
3 years ago
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