During the 2010 baseball season, the number of wins for three teams was three consecutive integers. Of these three teams, the
first team had the most wins. The last team had the least wins. The total number of wins by these three teams was 252. How many wins did each team have in the 2010 season?
Let the number of win for the teams be x, x+1 and x+2 respectively. From the question, we are told that the total number of wins by these three teams was 252 for the 2010 season. Therefore,
x+x+1+x+2 = 252
3x+3 = 252
3x = 252 - 3
3x = 249
x = 249/3
x = 83
This means that the team with least wins has 83 while the second team has 84 and the team with most wins has 85.
