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kotegsom [21]
3 years ago
13

The figure below shows the design of a truss to support the weight of a roof. In this truss design, ∠A⩭∠D and ĀF⩭DF.

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer:

m\angle A= 30^{\circ}

Step-by-step explanation:

In the question, we're given \angle A\cong \angle D. Therefore, the measure of these two angles must be equal.

To find the value of x, set these two angles equal to each other:

4x-26=x+16

Add 26 and subtract x from both sides:

3x=42

Divide both sides by 3:

x=\frac{42}{3}=14

Since \angle A was labelled as 4x-26, substitute x=14 to find its measure:

\angle A=4(14)-26,\\\angle A=56-26,\\\angle A=\boxed{30^{\circ}}

You can also substitute x=14 into the label of angle D as angle A is congruent to angle D for easier calculations (14+16=\boxed{30^{\circ}}).

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Ken's prediction for december was -5°c The actual low temperature was 3 degrees higher than his prediction what was the actual l
SashulF [63]

Answer:

  -2 °C

Step-by-step explanation:

Add 3 °C to get a temperature 3 °C higher.

  -5 °C + 3 °C = -2 °C

8 0
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alexira [117]

Answer:  16) \bold{\sqrt{x}}        (17) \bold{\dfrac{x-4}{2}}        (18) \bold{\sqrt{x}-2}       (19)  3x - 18

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and then solve for y

16) Given: y = x²

Swapped: x = y²

                \bold{\sqrt{x} =y}

17) Given:  y = 2x + 4

Swapped: x = 2y + 4

            x - 4 = 2y

            \bold{\dfrac{x-4}{2}=y}

18) Given:  y = (x + 2)²

Swapped: x = (y + 2)²

               √x = y + 2

        \bold{\sqrt{x}-2=y}

19) Given:  y=\dfrac{1}{3}x+6

Swapped: x=\dfrac{1}{3}y+6

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4 0
2 years ago
Here is a list of the normal monthly precipitation (in inches) for January for 20 different U.S. cities. 4.0, 1.0, 1.5, 1.6, 2.0
shutvik [7]

Answer:

minimum value = 1.0 , the lower quartile = 2.3, the middle value = 3.5.

the upper quartile = 3.95, the maximum value  = 7.3.

Step-by-step explanation:

Five Number Summary of any data consists basically of 5 data sets.

1) The minimum Value

2)The first (lower) quartile

3) The middle value (Median)

4) The third (upper) quartile

5)The maximum value

Now, the given data is  4.0, 1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.1, 5.8, 4.1, 7.3

Arrange it in the ascending order,

1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.0, 4.1, 4.1, 5.8, 7.3

Here,

1) The minimum Value  is 1.0

2)The first (lower) quartile  is  2.3.

3) The middle value (Median)  is 3.5.

4) The third (upper) quartile is  3.95.

5)The maximum value  is 7.3.

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olga nikolaevna [1]

Step-by-step explanation:

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