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Kisachek [45]
3 years ago
11

What statement is true about the graphs of the two lines y = -8x - 5/4 and y = 1/8x + 4/5?

Mathematics
1 answer:
stira [4]3 years ago
7 0

What statement is true about the graphs of the two lines y = -8x - 5/4 and y = 1/8x + 4/5?

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Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Tim spent $37.45 on groceries. On the way home, he wants to stop and pay cash for gas at $3.35 per gallon. If he started with $6
dalvyx [7]

Answer:

6.7

Step-by-step explanation:

60$-37.45=22.55

22.55/3.35=6.731

Which rounds to 6.7

5 0
3 years ago
What are the missing numbers help me
Aleksandr-060686 [28]
You are counting by 10s so the answer is 40,50,60,70,80
the complete sequence: 10,20,30,40,50,60,70,80,90,100
7 0
3 years ago
Read 2 more answers
A market sold two packages of sliced beef weighing 1 and one seventh and 4 and one half lb. What was the total weight of the bee
Pepsi [2]

Answer:

5 and 9/14

Step-by-step explanation:

convert the numbers into improper fractions

8/7 + 9/2

=

(8 × 2) + (9 × 7)

7 × 2

=

79/14   or 5 and 9/14


7 0
3 years ago
Read 2 more answers
Describe and correct the error in finding the area of the triangle.​
irina1246 [14]

Answer:

Height, base(4,1) to A(4,3)

Step-by-step explanation:

The height that is shown is incorrect as it is showing the distance between A and B, which is not the height of the triangle, and simply a side. We need to find the altitude(height) which is a line perpendicular to the base. If we draw a line that is perpendicular to the base that intersects the highest point of the triangle, A, we get the point of intersection of that line and the base at (4,1)

8 0
3 years ago
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