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Arte-miy333 [17]
3 years ago
14

An object is located 50 cm from a converging lens having a focal length of 15 cm. Which of the following is true regarding the i

mage formed by the lens?It is virtual, inverted, and smaller than the object.
It is real, inverted, and larger than the object.
It is real, upright, and larger than the object.
It is virtual, upright, and larger than the object.
It is real, inverted, and smaller than the object.
Physics
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

I'm pretty sure the correct answer is letter D. (The 4th one) virtual, upright, and larger than the object.

Explanation:

If the distance from a converging lens to the object is less than the focal length of the lens, the image will be virtual, upright, and larger than the object.

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Which receptors are responsible for the production of saliva (A) auditory receptors (B) optic receptors (C) skin receptors (D) t
Fudgin [204]

Answer:

\large \boxed{\sf D. \ taste \ receptors}

Explanation:

When activated, the receptor most likely prompting the production of saliva is the taste receptor. When food enters the mouth, the salivary glands produce the saliva upon the sensation of taste.

8 0
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If it takes 35J to lift up an object to some height, then how much gravitational potential energy will that object have?
uysha [10]
35j because if it takes so much to lift it’s that much pullin down
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A listener is sitting somewhere on the line between two loudspeakers that are 10 m apart. The speakers are each emitting a sine
prohojiy [21]

Answer:

57.17 Hz 114.34 Hz 285 Hz

Explanation:

The distance between the men and 1 speaker = 3.5 m

Distance between the men and second speaker = 10-3.5= 6.5 m

Here at this point there will be no sound so there will be destructive interference

Path difference \Delta x=6.5-3.5=3

We know that for destructive interference \Delta x=(2m+1)\frac{\lambda }{2}=(2m+1)\frac{v}{2f}

3=(2m+1)\frac{v}{2f}

f=(2m+1)\frac{v}{6} here v is the speed of sound in air

So for m =0

f=(2\times 0+1)\frac{343}{6}=57.17H

for m =1

f=(2\times 1+1)\frac{343}{6}=114.34Hz

for m=2

f=(2\times 2+1)\frac{343}{6}=285Hz

 

6 0
3 years ago
I don’t how to woke this
NeX [460]
Use the calculator to find out the answer
3 0
4 years ago
A sled with no initial velocity accelerates at rate of 5.0 m/s^2 down a hill . How long does it take the sled to go 45 m to the
Leya [2.2K]

The time taken by the sled to reach 45 m to the bottom is 4.24 s.

The sled's initial velocity <em>u</em> is zero. It has an acceleration <em>a</em> of a value 5 m/s² down the hill and it travels a distance <em>s</em> equal to 45 m down the hill.

Use the equation of motion,

s=ut+\frac{1}{2} at^2

Substitute 0 m/s for u and rewrite the equation for t.

t=\sqrt{\frac{2s}{a}}  \\ =\sqrt{\frac{2(45 m)}{5.0m/s^2} } \\ =4.24s

The sled takes a time of 4.24 s to reach the bottom of the hill

6 0
4 years ago
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