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hammer [34]
3 years ago
15

In triangle JKL, an angle bisector drawn from vertex K intersects the opposite side at point P.if JKL is 2y+25 and PKL is 8y - 1

7, what is the measure of JKL.show all of your work.

Mathematics
1 answer:
german3 years ago
4 0

Answer:

Therefore,

\angle JKL=34.08\°Step-by-step explanation:

Given:

KP is the angle bisector of ∠ JKL,

∠JKL = 2y + 25

∠ PKL = 8y - 17

To Find:

∠ JKL = ?

Solution:

KP is the angle bisector of ∠ JKL, .. given

Angle bisector divides the angle in two equal parts such that,

\angle JKL=2\times \angle PKL

Substituting the values we get

2y+25=2(8y-17)

Apply Distributive Property we get

2y+25=2\times 8y-2\times 17=16y-34\\\\16y-2y=34+25=59\\\\14y=59\\\\y=\dfrac{59}{14}=4.54

Now substitute y in JKL

\angle JKL=2 \times 4.54+25=34.08\°

Therefore,

\angle JKL=34.08\°

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