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Lady bird [3.3K]
3 years ago
6

Based on what you know about Earth's magnetic field what do you think about Mars' interior?

Chemistry
1 answer:
Tomtit [17]3 years ago
6 0

The interior of mars is rigid

Explanation:

To produce the magnetic field of the earth, the outer core is fluid and constantly moving.

  • The outer core is made up of metals
  • These metals are rich in iron and nickel and some other elements.
  • During the early formation of the earth, these minerals differentiated into this layer of the earth based on their density.
  • But the outer core region is molten and fluid.
  • The movement of these materials is responsible for the production of the geo-magnetic field that makes the earth behave like a bar magnet.

Mars has no magnetic field and we can suggest that its interior is rigid and solid.

Learn more:

Electromagnet brainly.com/question/2191993

#learnwithBrainly

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Explanation:

The atom is considered to be more electronegative , when it has the tendency to get a slight negative i.e. , delta negative charge on it , and the other atom gets a delta positive charge .

In the periodic table ,

As we go left to right in the periodic table , the electronegativity increases ,

and

As we go top to bottom , the electronegativity decreases .

Hence , from the option given in the question ,

a. C--H , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , Carbon is more electronegative than hydrogen .

b. C--N ,  the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , nitrogen is more electronegative than Carbon .

c. C--S , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , sulfur is more electronegative than Carbon .

d. C--O , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , oxygen is more electronegative than Carbon .

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What happens if I overshoot the endpoint in titration?
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How fast must a 56.5-g tennis ball travel in order to have a de Broglie wavelength that is equal to that of a photon of green li
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Answer:vv

v=2.17\times 10^{-26}\ m/s

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\lambda=\frac {h}{m\times v}

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Wavelength = 5400 Å = 5400\times 10^{-10}\ m

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5400\times 10^{-10}=\frac{6.626\times 10^{-34}}{0.0565\times v}

v=\frac{331300000}{10^{34}\times \:1.5255}\ m/s

v=2.17\times 10^{-26}\ m/s

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