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Ivan
3 years ago
7

The closeness of particles of gas and their low speeds allow intermolecular forces to become important at certain

Chemistry
1 answer:
My name is Ann [436]3 years ago
8 0
This is a limitation of the kinetic-molecular theory.
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1. Aluminium reacts with chlorine to produce aluminium chloride. The balanced reaction is:
Anton [14]

Answer:

Explanation:

es

6 0
3 years ago
How do I do letter D? Someone help me please
Minchanka [31]
So for D you have to find energy right
from c you get wavelength Lambda
so on D use this
E = Hc / lambda
c is given 1.5 x 10 ^20
h = 6.624 x 10^-34
and then you get answer for energy
8 0
3 years ago
The density of lead is 11.3g/cm^3 and the density of chromium is 7.14g/cm^3. If we have one gram of each metal, what is the rati
Lady bird [3.3K]

The ratio of the volume of lead to the volume of chromium is 22 : 35

Density is simply defined as the mass of a substance per unit volume of the substance.

<h3>Density = mass / volume </h3>

To solve the question given above, we'll begin by calculating the volume of lead and chromium. This can be obtained as follow:

<h3>For Lead:</h3>

Mass of lead = 1 g

Density of lead = 11.3 g/cm³

<h3>Volume of lead =? </h3>

Density = mass /volume

11.3 = 1 / Volume

Cross multiply

11.3 × Volume = 1

Divide both side by 11.3

Volume = 1 / 11.3

<h3>Volume of lead = 0.088 cm³</h3>

<h3>For Chromium:</h3>

Mass of chromium = 1 g

Density of chromium = 7.14 g/cm³

<h3>Volume of chromium =? </h3>

Density = mass /volume

7.14 = 1 / Volume

Cross multiply

7.14 × Volume = 1

Divide both side by 7.14

Volume = 1 / 7.14

<h3>Volume of chromium = 0.14 cm³</h3>

Finally, we shall determine the ratio of the volume of lead to the volume chromium. This can be obtained as follow:

Volume of lead = 0.088 cm³

Volume of chromium = 0.14 cm³

<h3>Ratio of the volume of lead to chromium =? </h3>

Ratio = Volume of lead / Volume of chromium

Ratio = 0.088 / 0.14

Ratio = 22 / 35

<h3>Ratio = 22 : 35</h3>

Therefore, the ratio of the volume of lead to the volume chromium is 22 : 35

Learn more: brainly.com/question/17262276

5 0
3 years ago
How many grams of HF are needed to react with 3.0 moles of Sn? *
Lostsunrise [7]

Answer:

120g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Sn + 2HF —> SnF2 + H2

Next, we shall determine the number of mole of HF needed to react with 3 moles of Sn.

From the balanced equation above, 1 mole of Sn reacted with 2 moles of HF.

Therefore, 3 moles of Sn will react with = 3 x 2 = 6 moles of HF.

Finally, we shall convert 6moles of HF to grams

This is illustrated below:

Number of mole of HF = 6moles

Molar Mass of HF = 1 + 19 = 20g/mol

Mass of HF =..?

Mass = number of mole x molar Mass

Mass of HF = 6 x 20

Mass of HF = 120g

Therefore, 120g of HF is needed to react with 3 moles of Sn

6 0
3 years ago
I NEED ANSWERS TO THESE PAGES
zmey [24]

Answer:

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6 0
3 years ago
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