The closeness of particles of gas and their low speeds allow intermolecular forces to become important at certain

Katyanochek1 [597]

Answer:

Mira la explicación.

Explanation:

Hola,

Las reacciones de oxidación se definen como aquellos procesos químicos en las cuales uno de los elementos involucrados sufre un aumento en su estado de oxidación, causado por el efecto de un agente oxidante, el cual es capaz de aceptar los electrones perdidos por dicho elemento oxidante. Dentro de los factores promotores de la oxidación se pueden encontrar:

1. Presencia de oxígeno gaseoso: al ser un agente oxidante fuerte, es capaz de recibir electrones de casi cualquier sustancia.

2. Presencia de humedad: a la larga, cuando una sustancia reacciona con agua tiende oxidarse ya que el agua posee oxígeno y como se vio anteriormente, es el principal promotor de oxidación.

3. La presencia de algunas sales iónicas como cloruro de sodio también promueven la oxidación, por ello es que no debemos introducir joyería al mar, debido a que esta salinidad induce reacciones electroquímicas que son capaces de oxidar metales.

4. Reacciones con ácidos oxidantes: ácidos como el nítrico, son oxidantes fuertes que tienen la capacidad de disolver metales (oxidarlos) y formar nitratos, por ejemplo el cobre en presencia de ácido nítrico, sufre una oxidación bastante violenta.

Saludos!

4 0

3 years ago

How is cloning different from hybridization?

kvasek [131]

1. Hybridization is a method of sexual reproduction whereas cloning is a method of asexual reproduction.

2. Hybrid animals are sterile, but cloned animals are fertile.

3. Hybrid organisms contain DNA from both male and female parents but cloned organisms contain DNA from only one type of parent.

4. Hybrid has superior character over its parents (improved hybrid vigor) but clones are 100% identical to their parent.

5. Hybridization gives only one hybrid progeny, whereas through cloning unlimited identical organisms can be produced.

6 0

3 years ago

If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce

Natali5045456 [20]

2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over

5 0

4 years ago

How many electrons in an atom can share the quantum numbers n=3, l =2 and m subscript l = 2? (1 point)

Rama09 [41]

Answer : The number of electrons in an atom is, 2 electrons

Explanation :

As we know that there are four quantum numbers which are principle quantum number, azimuthal quantum number, magnetic quantum number and spin magnetic quantum number.

The Principle quantum number, n = 3. That means the electron present in the third energy level.

The Azimuthal quantum number, l = 2. That means the electron present in the d sub-shell.

The magnetic quantum number, $m_l=2$ . That means it shows the 2 electrons present in one of the five 3d orbitals.

Hence, the number of electrons in an atom is, 2 electrons

8 0

3 years ago

The questions are attached

Sladkaya [172]

Answer:

Explanation:

a) Balanced chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

b) Mass of oxygen gas needed = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of oxygen and propane:

C₃H₈ : O₂

1 : 5

0.57 : 5/1×0.57 = 2.85 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 2.85 mol × 32 g/mol

Mass = 91.2 g

c) water vapors produced = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of water and propane:

C₃H₈ : H₂O

1 : 4

0.57 : 4/1×0.57 = 2.28 mol

Mass of water vapors:

Mass = moles × molar mass

Mass = 2.28 mol × 18 g/mol

Mass = 41.0 g

d)

mass of water vapors produced = 1.5 kg (1500 g)

Mass of propane reacted = ?

Solution:

Number of moles of water vapors:

Number of moles = mass/molar mass

Number of moles = 1500 g/ 18 g/mol

Number of moles = 83.33 mol

now we will compare the moles of water and propane.

H₂O : C₃H₈

4 : 1

83.3 : 1/4×83.3 = 20.8 mol

Mass of propane:

Mass = number of moles ×molar mass

Mass = 20.8 mol × 44.1 g/mol

Mass = 917 g

3 0

3 years ago