Answer:
The kinetic energy of the two stones is 320 J
Explanation:
Kinetic energy is the energy that a body possesses due to its movement. So it is the capacity or work that allows an object to go from being at rest, or still, to moving at a certain speed.
In other words, the kinetic energy of an object is that which is produced due to its motion and depends on its mass and velocity as follows:

where the kinetic energy Ec is measured in joules (J), the mass m is measured in kilograms (kg) and the velocity v in meters/second (m/s).
In this case you know that a 20 kg curling stone is sliding in a positive direction at 4 m/s. So:
Replacing you have:

Ec₁= 160 J
A second curling stone slides at the same speed but in the opposite direction. So:
Replacing you have:

Ec₂= 160 J
The kinetic energy of the two stones is calculated as:
Ec= Ec₁ + Ec₂
Ec= 160 J + 160 J
Ec= 320 J
<u><em>The kinetic energy of the two stones is 320 J</em></u>
Answer:
The estimated feed rate of logs is 14.3 logs/min.
Explanation:
The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.
That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.
Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.
To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.

The specific gravity of the wood chips is 0.494.
The average volume of a log is

The weight of one log is

To provide 3617 ton/day of wood chips, we need


The feed rate of logs is 14.3 logs/min.
Answer
Density = 7.87g/cm^3
Explanation:
Density is the ratio of mass of the given object to the volume of the object, in this question iron is the given object, then we make use of atomic number of iron
Given:
Length= 287pm = 287*10^-10cm
Atomic mass of Fe= 56.0u
Z=2(for body centered cubic unit cell)
Avogadro number (N 0)=6.022× 10^23
Density= ZM/a^3 × N
Where
Z= body centered cubic unit cell
Then substitute
N= Avogadro's number
a=Length
Density = (2× 56)/(287*10^-10cm)^3 × (6.022 × 10^23)
Density = 7.87g/cm^3
Answer:
CS2 is a non-polar molecule because it has a linear geometric shape with a symmetric distribution of charge. Simply put, there exists a 180° angle between the C-S bonds. This leads to the cancellation of the dipole moments arising due to each of the bonds.
Explanation: