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pentagon [3]
3 years ago
13

10. If you were running an experiment to determine the temperature at

Chemistry
1 answer:
Wittaler [7]3 years ago
6 0

Answer:

The temperature at which each bean is kept

Explanation:

Independent variable is what YOU CHANGE

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Please Help ASAP 100 points! Students set up a controlled experiment. They put five crickets in each of three identical containe
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They put five crickets in each of three identical containers. They s ... to 15°C, one to 20°C, and one to 25°C. Then they count the number of cricket chirps in each container

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What is the advantage of using Microsoft Excel to create a graph, as opposed to pen and paper?
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the advantage of using Microsoft Excel to create a graph, as opposed to pen and paper is it will help you get the right answer

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If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th
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At STP, the volume of a gas represents the number of particles.That said, from the chemical reaction one mole of oxygen reacts with two moles of co to produce the product, CO2At STP, 3 moles of Oxygen will produce 6 moles of CO2. Hence It follows that at standard temperature and pressure, 6.0 L of CO2 will be produced. Option D.
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What are the requirements for combustion of a candle?
cestrela7 [59]
For a candle to burn, it requires a spark, which provides the activation energy for the oxidation reaction of the hydrocarbon making the candle.
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7 0
3 years ago
Enough of a monoprotic acid is dissolved in water to produce a 1.64 M solution. The pH of the resulting solution is 2.82 . Calcu
Lady bird [3.3K]

Answer:

Ka = 1.39x10⁻⁶

Explanation:

A monoprotic acid, HX, will be in equilibrium in an aqueous medium such as:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

<em>Where Ka is:</em>

Ka = [H⁺] [X⁻] / [HX]

<em>Where [] is the molar concentration in equilibrium of each specie. </em>

The equilibrium is reached when some HX reacts producing H+ and X-, that is:

[HX] = 1.64M - X

[H⁺] = X

[X⁻] = X

As pH is 2.82 = -log [H⁺]:

[H⁺] = 1.51x10⁻³M:

[HX] = 1.64M - 1.51x10⁻³M = 1.638M

[H⁺] = 1.51x10⁻³M

[X⁻] = 1.51x10⁻³M

And Ka is:

Ka = [1.51x10⁻³M] [1.51x10⁻³M] / [1.638M]

<h3>Ka = 1.39x10⁻⁶</h3>
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3 years ago
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