10. If you were running an experiment to determine the temperature at
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Answer:
See explanation.
Explanation:
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In this case, according to the given information, it turns out possible for us to firstly recall the electron configuration of hydrogen:
To realize that the principal quantum number is 1, the angular is 0 as well as the magnetic one; therefore we infer that all the given n's are not allowed, just l=0 is allowed as well as ml=0 yet the rest, are not allowed.
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Answer:- 0.273 kg
Solution:- A double replacement reaction takes place. The balanced equation is:
We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.
= 63.8 g aluminum nitrate
From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.
We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.
=
sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.
= 0.273 kg
So, 0.273 kg of 35% m/m sodium chlorate solution are required.
24.25 moles of NO can be produced using 97 moles of HNO3.
<h3>What is balanced chemical equation?</h3>Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Varied elements' atom counts in the reactants and products of unbalanced chemical equations are different.
3 Cu + 8HNO3 g → 3 Cu(NO3)2 + 2 NO + 4 H2O
The number of moles consumed can be calculated using comparing with coefficients in the balanced reaction .
So , from above eq we get that 8 moles of HNO3 are consumed to make 2 moles of NO.
⇒ 8 HNO3⇔2 NO
⇒ 1 HNO3⇔ 1/4 NO
This means that for each mole of HNO3 produces 1/4 moles of NO.
So , for 97 moles of HNO3 , moles of NO can be made,
So, total moles of NO made are 24.25 moles.
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