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3 years ago

Unlabeled atoms joined to carbon atoms, which are not directly part of a ring structure, are assumed to be oxygen atoms.

1 answer:

N76 [4]3 years ago

3 0

The statement above is FALSE.
Unlabeled atom joined to carbon atoms which are not directly part of a ring structure are assumed to be CARBON ATOMS. In a ring structure, an unlabeled atom at the angle where two lines joined together is always assumed to be a carbon atom

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12. Identify the following as a chemical or physical change:

Reika [66]

I think the answer isD,A

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3 years ago

7. A nonpolar covalent bond (i.e., pure covalent) would form in which one of the following pairs of atoms? A) Na Cl B) H Cl C) L

padilas [110]

Answer:

E) Br Br

Explanation:

Covalent bond -

Covalent bond is the bond which is formed with the sharing of the electrons between the two atoms which are taking part in the bond. It is generally formed between the atoms with similar electronegativity values.

It is the bond which is generally occurs within non metals as they share electrons to complete their octet.

The difference in the electronegativity values of the atoms involving in a covalent bond must not exceed the value of 1.7 .

A covalent bond to be non polar in nature , then the atoms need to have almost similar electronegativity , so that they won't split into partial negative and partial positive charge .

Hence , from the given options of the question ,

E) Br Br , both the atoms are same , hence same electronegativity , therefore are non - polar in nature .

8 0

2 years ago

A hydrogen-like ion is an ion containing only one electron. The energies of the electron in a hydrogen-like ion are given by the

yan [13]

Answer:

The ionization energy (in kJ/mol) of the helium ion is 21,004.73 kJ/mol .

Explanation:

$E_n = -(2.18 10-18 J)\times \frac{Z^2}{n^2}$

Z = atomic mass

n = principal quantum number

Energy of the electron in n=1,

$E_1= -(2.18 10^{-18} J)\times \frac{4^2}{1^2}=-3.488\times 10^{-17} J$

Energy of the electron in n = ∞

$E_{\infty}= -(2.18 10^{-18} J)\times \frac{2^2}{\infty ^2}=0 J$

Ionization energy of the $He^+$ ion:

$I.E=E_{infty}-E_1=0-(-3.488\times 10^{-17} J)=3.488\times 10^{-17} J$

$I.E=3.488\times 10^{-20} kJ$

To convert in into kj/mol multiply it with $N_A=6.022\times 10^{23} mol^{-1}$

$I.E=3.488\times 10^{-20} kJ\times 6.022\times 10^{23} mol^{-1}=21,004.73kJ/mol$

3 0

2 years ago

Read 2 more answers

A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.

Lilit [14]

Answer:

The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

$\frac{V1}{T1} = \frac{V2}{T2}$

Solve for V2

V2 = $\frac{V1T2}{T1}$

3.- Substitution

V2 = $\frac{(42)(233)}{293}$

4.- Simplification

V2 = $\frac{9786}{293}$

5.- Result

V2 = 33.4ml

3 0

2 years ago

Why are metal containers not used for storing acids

kaheart [24]

Answer : Metal containers are not used for storing acid because most of the time acid reacts with almost every metal and produces salts or oxides which alters the acid characteristics making it useless .......

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2 years ago