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Illusion [34]
3 years ago
8

Identify the conjugate acid-base pair in this balanced equation: H2SO4 + 2NaOH → 2H2O + Na2SO4

Chemistry
2 answers:
Ludmilka [50]3 years ago
4 0
H2SO4/H2O
H2SO4/Na2SO4
NaOH/H20
NaOH/Na2SO4
Correct answer is H2SO4/Na2SO4
kipiarov [429]3 years ago
3 0

Answer is: H₂SO₄/Na₂SO₄.

Chemical dissociation of sulfuric acid in water:  

H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq).

Sulfuric acid is strong diprotic acid. It dissociates on hydrogen cations (H⁺) and sulfate anion (SO₄²⁻).

Sulfate anion is conjugate base of sulfuric acid.

According to  Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺).

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The diffrent names for the diffrent ways the moon can look from earth or blank?
Gnesinka [82]


there are 8 moon phases.

They are - First quarter, waxing crescent, new, waning crescent, third quarter, Waning gibbous, full, and waxing gibbous

8 0
3 years ago
When the equation below is correctly balanced, the coefficient for CO2 is
vaieri [72.5K]

Answer:

The answer to your question is 4

Explanation:

Chemical reaction

                C₂H₆  +  O₂  ⇒  CO₂  +  H₂O

           Reactants    Elements    Products

                  2            Carbon              1

                  6            Hydrogen         2

                  2            Oxygen             3

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒  4CO₂  +  6H₂O

           Reactants    Elements    Products

                  4            Carbon             4

                 12            Hydrogen       12

                 14            Oxygen           14

When the reaction is balanced the coefficient for CO₂ is 4.

5 0
2 years ago
If a Ferrari with an initial velocity of 10m/s accelerates at a rate of 5m/s2 for 3 seconds. What will it’s final velocity be?
Reika [66]

Answer:

<em><u>V = 25 m/s</u></em>

Explanation:

From first equation of motion, V = U + at

V = 10 + ( 5×3 )

V = 25 m/s

4 0
2 years ago
A gaseous mixture of 10.0 volumes of CO₂, 1.00 volume of unreacted O₂, and 50.0 volumes of unreacted N₂ leaves an engineat 4.0 a
ycow [4]

The masses of CO and CO2​ are 90.55g and 100−90.55=9.45 g respectively.

<h3>Total mass.</h3>

Let the mixture has 100g as total mass.

The number of moles of CO is 2890.55​=3.234.

The number of moles of CO2​ is 449.45​=0.215.

The mole fraction of CO is 3.234+0.2153.234​=0.938.

The mole fraction of CO2​ is 1−0.938=0.062.

The partial pressure of CO is the product of the mole fraction of CO and the total pressure.

It is 0.938×1=0.938 atm.

The partial pressure of carbon dioxide is 0.062×1=0.042 atm.

The expression for the equilibrium constant is:

Kp​=PCO2​​PCO2​​=0.062(0.938)2​=14.19

Δng​=2−1=1

Kc​=Kp​(RT)−Δn=14.19×(0.0821×1127)−1=0.153.

To learn more about equilibrium constant visit the link

brainly.com/question/15118952

#SPJ4

3 0
1 year ago
NEED AN ANSWER URGENTLY !!!
pshichka [43]

I think the answer is D.

6 0
3 years ago
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