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2 years ago

Identify the conjugate acid-base pair in this balanced equation: H2SO4 + 2NaOH → 2H2O + Na2SO4

Chemistry

2 answers:

Ludmilka [50]2 years ago

4 0

H2SO4/H2O
H2SO4/Na2SO4
NaOH/H20
NaOH/Na2SO4
Correct answer is H2SO4/Na2SO4

kipiarov [429]2 years ago

3 0

Answer is: H₂SO₄/Na₂SO₄.

Chemical dissociation of sulfuric acid in water:

H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq).

Sulfuric acid is strong diprotic acid. It dissociates on hydrogen cations (H⁺) and sulfate anion (SO₄²⁻).

Sulfate anion is conjugate base of sulfuric acid.

According to Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺).

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Calculate the number of grams of oxygen required to convert 48.0 g of glucose to co2 and h2o.

worty [1.4K]

I believe that the balanced chemical reaction is:

C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

So the number of grams of oxygen required is:

mass O2 required = 48 g C6H12O6 * (1 mole C6H12O6 / 180.16 g) * (6 mole O2 / 1 mole C6H12O6) * (32 grams O2 / 1 mole)

mass O2 required = 51.15 grams

4 0

3 years ago

What most accurately explains whether liquid water or ice has a higher density, and why?

nata0808 [166]

Answer:

I think your answer is either b or c but I think b is more likely to be your answer

7 0

2 years ago

What would the product look like if ROOR weren't used?

S_A_V [24]

Answer:

The least substituted product (anti-Markovnikov)

Explanation:

The ROOR is used in the addition reaction of HBr to an organic substance (an alkene for example).

In normal conditions (with no ROOR) the adition of the halogen will be performed in the most substituted C (following the rule of Markovnikov that says that the stability increases with the more substituted is the C).

But in presence of ROOR, the reaction takes other mechanism (free radicals), and the product in this case is the one with the Br added in the least substituted C.

4 0

2 years ago

Name a compound containing bromine and iodine

Mama L [17]

Synthesis. Iodine monobromide is formed when iodine and bromine are combined in a chemical reaction: I2 + Br2 → 2 IBr.

4 0

2 years ago

Scoring: Your score will be based on the number of correct matches minus the mumber of incorrect matches. There is no penalty fo

Yakvenalex [24]

Answer:

a. There is little or no change in the entropy.

b. ΔS is greater than zero.

c. There is little or no change in the entropy.

d. ΔS is less than zero.

e. ΔS is greater than zero.

Explanation:

The change in the entropy (ΔS) depends on the change in the amount of gaseous moles, Δn(g) = ngas, products - ngas,reactants.

If Δn(g) > 0, the entropy increases (ΔS > 0)
If Δn(g) < 0, the entropy decreases (ΔS < 0)
If Δn(g) = 0, there is little or no change in the entropy.

a. I₂(g) + Cl₂(g) → 2 ICl(g)

Δn(g) = 2 - 2 = 0. There is little or no change in the entropy.

b. PCl₅(g) → PCl₃(g) + Cl₂(g)

Δn(g) = 2 - 1 = 1. ΔS is greater than zero.

c. CO₂(g) + H₂(g) → H₂O(g) + CO(g)

Δn(g) = 2 - 2 = 0. There is little or no change in the entropy.

d. 2 CO(g) + 2 NO(g) → 2 CO₂(g) + N₂(g)

Δn(g) = 3 - 4 = -1. ΔS is less than zero.

e. 2 H₂O₂(l) → 2 H₂O(l) + O₂(g)

Δn(g) = 1 - 0 = 1. ΔS is greater than zero.

4 0

2 years ago