The answer to this question would be A
Answer: D. 19.9 g hydrogen remains.
Explanation:
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.0787 moles of require= of
Thus is the limiting reagent as it limits the formation of product and acts as the excess reagent. (10.0-0.0787)= 9.92 moles of are left unreacted.
Mass of
Thus 19.9 g of remains unreacted.
Answer:
The answer of this question is 3
Explanation:
aam= 90%•20amu+10%•22amu/100
aam= 2020/100
aam= 20.2