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Ilya [14]
3 years ago
5

Two marbles (m = 0.050 kg each) moving on a table TOWARDS each other with the speed of 0.3 m/s collide, and start moving away fr

om each other.
a) What is the total momentum of this system before the collision?
V1 = __________ m/s, V2 = __________ m/s,

p1 = __________ kg m/s, p2 = __________ kg m/s,

ptotal = ____________ kg m/s
Physics
1 answer:
snow_tiger [21]3 years ago
7 0

Answer:

V1 = ____0.3______ m/s, V2 = ____-0.3______ m/s,

p1 = ____0.015______ kg m/s, p2 = ___-0.015_______ kg m/s,

ptotal = _0___________ kg m/s

Explanation:

Taking the marble ball that moves from right to left as Marble 1 and the one that moves from left to right as Marble 2. We take direction from left to right as negative and from right to left as positive. Therefore, velocity of marble 1 will be +0.3 m/s while velocity of marble 2 will be -0.3 m/s. The mass of marble 1, m2 0.05 Kg and same to marble 2, m2=0.05 Kg

Momentum is product of mass and velocity hence using p to represent momentum

P1=0.05*0.3=0.015 Kg m/s

P2=0.05*-0.3=-0.015 Kg m/s

V1=0.3 m/s, V2=-0.3 m/s

The total momentum before collision will be the sum of P1 and P2 hence 0.015 Kg m/s+-0.015 Kg m/s=0

Ptotal=0 Kg m/s

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a) greater

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Answer: A.Validate and implement the results.

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Is the classification for an instrument that produces sound whne a string or strings stretched between two points is plucked?
Yuki888 [10]
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2 years ago
Consider three planets. All have the same mass as Earth, but with different radii (from largest to smallest: Planet 1, 2, 3). Fo
LuckyWell [14K]

Answer:

option C

Explanation:

given,

mass of the three planet is same

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expression of escape velocity

v = \sqrt{\dfrac{2GM}{R}}

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

from the above expression we can clearly conclude that the escape velocity is inversely proportional to the radius of the Planet.

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3 0
3 years ago
An uncharged series RC circuit is to be connected across a battery. For each of the following changes, determine whether the tim
slavikrds [6]

a) Increase

b) Unchanged

c) Increase

Explanation:

a)

The charge on a capacitor charging in a RC circuit connected to a battery follows the exponential equation:

Q(t)=Q_0 (1-e^{-\frac{t}{RC}})

where

Q_0 = CV is the final charge stored in the capacitor, where C is the capacitance and V is the voltage of the battery

t is the time

R is the resistance of the circuit

The capacitor reaches 90% of its final charge when

Q(t)=0.90Q_0

Substituting and re-arranging the equation, we find:

0.90Q_0 = Q_0(1-e^{-\frac{t}{RC}})\\0.90=1-e^{-\frac{t}{RC}}\\e^{-\frac{t}{RC}}=0.10\\-\frac{t}{RC}=ln(0.10)\\t=-RCln(0.10)=2.30RC

We see that if we double the RC constant, then (RC)'=2(RC)

So the time taken will double as well:

t'=2.30(RC)'=2.30(2RC)=2(2.30RC)=2t

So, the answer is "increase"

b)

In this second part, the battery voltage is doubled.

According to the equation written in part a),

Q_0 =CV

this means also that the final charge stored on the capacitor will also double.

However, the equation that gives us the time needed for the capacitor to reach 90% of its full charge is

t=2.30 RC

We see that this equation does not depend at all on the voltage of the battery.

Therefore, if the battery voltage is doubled, the final charge on the capacitor will double as well, but the time needed for the capacitor to reach 90% of its charge will not change.

So the correct answer is

"unchanged"

c)

In this case, a second resistor is added in series with the original resistor of the circuit.

We know that for two resistors in series, the total resistance of the circuit is given by the sum of the individual resistances:

R=R_1+R_2

Since each resistance is a positive value, this means that as we add new resistors, the total resistance of the circuit increases.

Therefore in this problem, if we add a resistor in series to the original circuit, this means that the total resistance of the circuit will increase.

The time taken for the capacitor to reach 90% of its final charge is still

t=2.30 RC

As we can see, this time is directly proportional to the resistance of the circuit, R: therefore, if we add a resistor in series, the resistance of the circuit will increase, and therefore this time will increase as well.

So the correct answer is

"increase"

8 0
2 years ago
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