You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.How muc
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Answer:
The total distance will be 400 m.
Explanation:
For portion AB:
Acceleration = 2
t= 10 s
Car start from rest , u=0 m/s
We know that
S= 100 m.
For portion BC:
V= u + at
V=0 + 2 x 10
V= 20 m/s
In this portion car moves with constant velocity 20 m/s for 10 s.
So distance S= V x t
S=20 x 10 =200 m.
For portion CD:
The velocity at point C will be 20 m/s
In this portion the final speed of car will be zero because given that at final car come to rest.
So the acceleration will be in the negative direction to stop the car.
We know that
S=100 m
The total distance AD=AB + BC+ CD
AD=100 +200 + 100 m
AD=400 m.
The total distance will be 400 m.
