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sergij07 [2.7K]
2 years ago
8

Nasa has developed deep-space 1 (ds-1), a spacecraft that is scheduled to rendezvous with the asteroid named 1992 kd (which orbi

ts the sun millions of miles from the earth). the propulsion system of ds-1 works by ejecting high-speed argon ions out the rear of the engine. the engine slowly increases the velocity of ds-1 by about +9.23 m/s per day. (a) how many days will it take to increase the velocity of ds-1 by +3440 m/s? (b) what is the acceleration of ds-1?
Physics
1 answer:
andrezito [222]2 years ago
6 0
I can't give an exact number if the original velocity of ds-1 is not given. In that case, the final answer should just be in terms of an equation. Let's denote the original velocity to be v₀ and the days to be d.

Part a.)
v = v₀ + 9.23d
3440 = v₀ + 9.23d
9.23d = 3,440 - v₀
d = (3,440 - v₀)/9.23

Part b.)

The acceleration is the change in velocity per unit time. So, that would be 9.23 m/s per day. Since there are 86,400 s in a day:

a = 9.23 m/s / day * 1 day/ 86,400 s
a = 0.0001068 m/s²
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v=(6ti+6k)\ m/s

Explanation:

Given that,

The position of a particle is given by :

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Let us assume we need to find its velocity.

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v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s

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3 years ago
A red blood cell is 7 x 10-6 m in size. This means it is 7 __________ in size. What unit completes the sentence?
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If a red blood cell is 7 x 10^-^6 m in size, it means that such a cell is 7 microns or micrometer in size. The unit that completes the sentence will, thus, be microns or micrometer.

According to international system of measurement:

  • 10^{-1} m = decimeter
  • 10^{-2} m = centimeter
  • 10^{-3} m = millimeter
  • 10^{-6} m = micrometer or micron
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Thus, a measurement of 7 x 10^-^6 m is the same is 7 micons or 7 micrometer.

More on metric conversion can be found here: brainly.com/question/17767575

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2 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
spin [16.1K]

Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

f = f_{0}\frac{v + v_{o}}{v - v_{s}}        

Where:

f₀: is the emitted frequency

f: is the frequency heard by the observer  

v: is the speed of the sound = 343 m/s

v_{o}: is the speed of the observer = 0 (it is heard in the town)

v_{s}: is the speed of the source =?

The frequency of the train before slowing down is given by:

f_{b} = f_{0}\frac{v}{v - v_{s_{b}}}  (1)                  

Now, the frequency of the train after slowing down is:

f_{a} = f_{0}\frac{v}{v - v_{s_{a}}}   (2)  

Dividing equation (1) by (2) we have:

\frac{f_{b}}{f_{a}} = \frac{f_{0}\frac{v}{v - v_{s_{b}}}}{f_{0}\frac{v}{v - v_{s_{a}}}}

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - v_{s_{b}}}   (3)  

Also, we know that the speed of the train when it is slowing down is half the initial speed so:

v_{s_{b}} = 2v_{s_{a}}     (4)

Now, by entering equation (4) into (3) we have:

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - 2v_{s_{a}}}  

\frac{300 Hz}{290 Hz} = \frac{343 m/s - v_{s_{a}}}{343 m/s - 2v_{s_{a}}}

By solving the above equation for v_{s_{a}} we can find the speed of the train after slowing down:

v_{s_{a}} = 11.06 m/s

Finally, the speed of the train before slowing down is:

v_{s_{b}} = 11.06 m/s*2 = 22.12 m/s

Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.                        

I hope it helps you!                                                        

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