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frutty [35]
3 years ago
11

A luge run is straight for the first 10 m. If the velocity of the luger when he passes the start line is +25 m/s and his acceler

ation is constant at +9.5 m/s2, about how fast is he going when he hits the first turn?
Physics
1 answer:
dangina [55]3 years ago
3 0
V^2 =U^2 +2AS
V^2 = 25 ^2 + 2x9.5x10
V^2 = 625 + 1900 = 2525
V = 50.25
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What is a mixture of rock and mineral fragments, organic matter, air, and water called?
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3 years ago
A long solenoid of radius 3 cm has 1100 turns per meter. If the solenoid carries a current of 1.5 A, then calculate the magnetic
Arada [10]

Answer:

The magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

Explanation:

The magnetic field B at the center of the solenoid is given by

B = μ₀ni where μ₀ = permeability of free space = 4π × 10⁻⁷H/m, n = number of turns per unit length of the solenoid = 1100 turns per meter and i = current in the solenoid = 1.5 A.

So B = μ₀ni

= 4π × 10⁻⁷H/m × 1100 × 1.5 A

= 4π × 10⁻⁷H/m × 1650 A-turns/m

= 20734.5 × 10⁻⁷T  

= 2.07345 × 10⁻³ T

≅ 2.1  × 10⁻³ T

So the magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

3 0
3 years ago
3.
lozanna [386]

The force of gravity produces acceleration in all C. freely falling objects and this is known as acceleration due to gravity

Explanation:

A body is said to be in free fall when there is only one force acting on the body: the force of gravity.

Gravity is a force that acts downward, i.e. towards the Earth's centre.

If we are near the Earth's surface, the magnitude of the force of gravity on a body is given by

F=mg

where:

m is the mass of the body

g is known as the acceleration of gravity , whose value near the Earth's surface is 9.8 m/s^2).

We can apply Newton's second law on an object in free-fall, to find its acceleration. In fact, we have:

F=ma

where F is the force acting on the body and a is its acceleration.

Solving for the acceleration,

a=\frac{F}{m}

And substituting F,

a=\frac{mg}{m}=g=9.8 m/s^2

Therefore, every object in free-fall accelerates at 9.8 m/s^2 towards the ground.

Learn more about free fall here:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

8 0
3 years ago
What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-
sergey [27]

q = -21 * 10^{-6} C

<h3>What is Free-fall acceleration?</h3>

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 m/s at sea level on the Earth.

As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force,

mg =qE

1.45 * 10^{-3}(9.80)=q(600)\\\\q = 21 *10^{6} C\\\\

and its sign must be negative so that it will have upward electric force

so it is

q = -21 * 10^{-6} C

The charge of a particle of mass is -21 * 10^{-6} C

Learn more about Free-fall acceleration: brainly.com/question/2165771

#SPJ1

8 0
2 years ago
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