From my notes it’s the ability to do work
The vertical displacement of the wave is measured from
the equilibrium to the crest and is called the amplitude.
M = 40 Kg , g=9.8 m/s² , h = 2 m
PE = m g h
PE = (40) (9.8) (2)
PE = 784 J
KE = PE
½m v² = m g h
½ v² = g h
½ v² = (9.8) (2)
½ v² = 19.6
v² = 19.6×2
v² = 39.2
V = √39.2
V = 6.26 m/s
KE = ½mv²
KE = ½(40) (6.26)²
KE =783.8 J
Answer:
We conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.
Explanation:
Given
To determine
We need to find the quantity of the charge that flows through the wire in 50 s.
Important Tip:
A current of 1 Ampere = 1 Coulomb of charge flowing in 1 second
Using the formula involving charge and current

where:
represents the current in amperes (A)
represents the charge in coulomb (C)
represents the time in seconds (s)
now substituting I = 0.9 and t = 50 in the formula


switch sides

Multiply both sides by 50

Simplify
C
Therefore, we conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.
(150 km/hr) x (1000 m/km) x (hr/3600sec) = 41-2/3 m/sec
Acceleration = (change in speed) / (time for the change)
Change in speed = (41-2/3 minus 0) = 41-2/3 m/s
Time for the change = 0.5sec.
Acceleration = (41-2/3 m/s) / (0.5 sec) = 83-1/3 m/s² .
Acceleration of gravity = 9.8 m/s² .
Acceleration of sneezed air = (83-1/3) / (9.8) = <em>8.5 g </em>(rounded)