Question

A golf ball was hit with an initial velocity of 12 meters per second off the ground. The height of the ball after x seconds is modeled by the equation h(x)=-4.8x(x-2.5)

Answer 1

The ball hits the ground at 0 seconds or 2.5 seconds.

h represents the height of the golf ball after x seconds. The height is given by:

h(x)=-4.8x(x-2.5)

h(x) = -4.8x² + 12x

The time taken for the ball to reach the ground is at h(x) = 0, hence:

0 = -4.8x² + 12x

4.8x² - 12x = 0

x(4.8x - 12) = 0

hence x = 0; or 4.8x - 12 = 0

x = 0; or x = 2.5

Therefore the ball hits the ground at 0 seconds or 2.5 seconds.

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