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Troyanec [42]
3 years ago
7

Annie estimates that the height of a bookcase is 78.25 in. The actual height is 75.50 in. To the nearest tenth of a percent, wha

t is the percent error in Annie's estimate? Enter your answer in the box.
Mathematics
2 answers:
Vinil7 [7]3 years ago
6 0

Answer  

Find out the  percent error in Annie's estimate .

To prove

Formula

Percentage\ error = \frac{error\times 100}{exact\ value}

As  error = approx value -  exact value

As given

Annie estimates that the height of a bookcase is 78.25 in.

The actual height is 75.50 in.

approx value = 78.25 in.

actual value = 75.50 in.

error = 78 .25 - 75 .50

        = 2.75

put in the formula

Percentage\ error = \frac{2.75\times 100}{75.50}

Percentage\ error = \frac{27500}{7550}

Percentage error = 3.64 % (approx)

Therefore the Percentage error be 3.64 % (approx).

Colt1911 [192]3 years ago
3 0
3.6 is my answer.....

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Artyom0805 [142]
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8 0
3 years ago
If tñ=2ñ+3, find S10​
Allisa [31]

Answer:

S_{10}=280

Step-by-step explanation:

Given that,

t_n=2n+3 ...(1)

We need to find the value of S_{10}.

Put n = 1 to find the first term.

t_1=2(1)+3=5

Put n = 2 to find the second term.

t_2=2(2)+3=7

Put n = 3 to find the third term.

t_3=2(3)+3=9

Put n = 10 to find the tenth term.

t_{10}=2(10)+3=23

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

S_=\dfrac{n}{2}(a+a_n)

We have, n = 10, a = 5 and a_n=23

So,

S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280

So, the value of S_{10} is equal to 280.

3 0
3 years ago
Two number cubes are rolled.
yaroslaw [1]

Answer:

1/4

Step-by-step explanation:

Assuming the number cube is a six-faced die, you have

1 <u>2</u> 3 <u>4</u> 5 <u>6</u>

three odd numbers, and three even numbers. Therefore, the chance of it landing on an odd number or even number is 3/6, which equals 1/2. <em>That means you have a 50% chance to get an odd number, or an even number.</em>

<em />

So, you have two die. Both have a 50/50 chance of getting an even or odd number. So what's the chance of one landing on an odd number, and the other landing on an even number?

  • You would have a 25% chance for an <u>even</u> and then an <u>even</u> number
  • You would have a 25% chance for an <u>odd</u> and then an <u>odd</u> number
  • You would have a 25% chance for an <u>even</u> and then an <u>odd</u> number
  • You would have a 25% chance for an <u>odd</u> and then an <u>even</u> number.

25% as a simplified fraction is 1/4. Therefore, 1/4 is your answer.

8 0
3 years ago
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Can someone help me with this question??
maksim [4K]

Answer:

QT < TR.

Step-by-step explanation:

QT = TR because TZ is a mid segment so QT < TR is false.

6 0
4 years ago
5 Wyatt had one sack that contained some
defon

Answer:

Step-by-step explanation:

the answer is 1/4

7 0
3 years ago
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