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2 years ago

Decide if the following biconditional statement is true or false:

Mathematics

2 answers:

ozzi2 years ago

4 0

Answer:

False

Step-by-step explanation:

I know what I talking about and I'm right

rewona [7]2 years ago

4 0

This statement is false because December is not the only month when it is winter. January February and March are also in winter.

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2 years ago

Read 2 more answers

For the polynomial function ƒ(x) = x4 −25x2, find the zeros. Then determine the multiplicity at each zero and state whether the

Veronika [31]

<u>ANSWER</u>

The zeros are $x=-5,x=0,x=5$

EXPLANATION

Given;

$f(x)=x^4-25x^2$ .

We can rewrite the function as

$f(x)=x^2(x^2-25)$

$\Rightarrow f(x)=x^2(x^2-5^2)$

$\Rightarrow f(x)=x^2(x-5)(x+5)$

The zeros are found by equating the function to zero.

$\Rightarrow x^2(x-5)(x+5)=0$

$\Rightarrow (x-5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=5$

$\Rightarrow (x+5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=-5$

$\Rightarrow x^2=0$

This last root has a multiplicity of 2.

That is

$x=0$ repeats two times.

Since the multiplicity is even, the graph touches the x-axis at the point $x=0$ .

See graph.

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2 years ago