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mylen [45]
3 years ago
9

2.3c. What is the frequency of a wave with a length of 12 m that travels at a speed of 36 m/s?

Physics
1 answer:
MatroZZZ [7]3 years ago
6 0

the frequency of the wave is 3
36/12= 3

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What does the sun consume to produce energy and helium?
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This reaction, known as nuclear fusion, converts hydrogen atoms into helium. The by-product of nuclear fusion in theSun's core is a massive volume ofenergy that gets released and radiates outward toward the surface of the Sunand then into the solar system beyond it.



just reword it
3 0
3 years ago
Read 2 more answers
If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either
Verdich [7]

Answer:

Height h= 1.7 m

Explanation:

Supposing we have to find height in meter.

1 feet = 0.3048 m

1 inch = 0.0254 m

Given that:

5 feet

= 5×0.3048

= 1.524 m

and 7 inch = 7×0.0254= 0.1778 m

Therefore total height of a man in meter

5 feet 7 inch = 1.5424+0.1778 =1.7 m

Height h= 1.7 m

3 0
4 years ago
you have two pendulums with cords that are exactly the same length. one is on earth (with an acceleration due to gravity of 9.81
olga55 [171]
From  T = 2π√(l/g).

Since the lengths are the same, so that is a constant.

T α 1/√g

So the period T is inversely proportional to the square root of gravity g.

So the one with a bigger gravity g would have a shorter period

and

the one with smaller gravity g would have a longer period.

Therefore the period on the Moon with gravity of 1.63 m/s² would be longer period than that on the Earth with gravity of 9.81 m/s² 
8 0
3 years ago
harge of uniform density (100 nC/m3) is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical sur
Elden [556K]

Answer:

The magnitude of the electric field is 8.47 N/C

Explanation:

Given;

uniform charge density, λ = 100 nC/m³

inner radii of the cylinder, r =  1.0 mm and 3.0 mm

distance from the symmetry axis, R = 2.0 mm

Volume =\pi (R^2 -r^2)l\\\\Volume =\pi ((2*10^{-3})^2 -(1*10^{-3})^2)l\\\\Volume =\pi (4*10^{-6} - 1*10^{-6})l\\\\Volume = 3*10^{-6} \pi l \ m^3

Area = 2πrl

Area =2π(2 x 10⁻)l

Volume = A x d

d = Volume / Area

d = \frac{V}{A} = \frac{3*10^{-6}*\pi*l}{4\pi *10^{-3} l} = 75 *10^{-5} \ m

the magnitude of the electric field

E = \frac{\lambda *d}{\epsilon_o} = \frac{100*10^{-9} *75*10^{-5}}{8.854*10^{-12}} \\\\E = 8.47 \ N/C

Therefore, the magnitude of the electric field is 8.47 N/C

6 0
3 years ago
A 0.900 kg block is attached to a spring with spring constant 14.5 N/m . While the block is sitting at rest, a student hits it w
olga55 [171]

Answer:

1. A=0.0847\ m

2. v=0.050\ m.s^{-1}

Explanation:

Given:

  • mass of block, m=0.9\ kg
  • spring constant, k=14.5\ N.m^{-1}
  • maximum velocity of block, v_m=34\ cm.s^{-1}

1.

<u>We know from the energy of oscillating spring:</u>

E=\frac{1}{2}.k.A^2= \frac{1}{2}.m.v_m^2

\frac{1}{2}\times 14.5\times A^2=\frac{1}{2}\times 0.9\times 0.34^2

A=0.0847\ m

2.

Now, given that:

instantaneous position, x=0.15\times A=0.0127\ m

we find angular speed,

\omega=\sqrt{\frac{k}{m} }

\omega=\sqrt{\frac{14.5}{0.9} }

\omega=4.013\ rad.s^{-1}

So we have

v=x.\omega

v=0.0127\times 4.013

v=0.051\ m.s^{-1}

7 0
4 years ago
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