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sergey [27]
4 years ago
11

Which statement correctly distinguishes between all mechanical and all electromagnetic waves?

Physics
2 answers:
Sunny_sXe [5.5K]4 years ago
7 0

Answer:

B

Explanation:

Mechanical waves carry energy through matter; electromagnetic waves carry energy through space.

lutik1710 [3]4 years ago
3 0

Answer: Mechanical waves carry energy through a medium; electromagnetic waves carry energy through media and space.

Explanation:

<u>The waves which require medium to travel are known as mechanical waves. </u>The waves carry energy forward by compression and rarefaction that is by changing density /pressure of medium particles.

<u>Electromagnetic waves can transfer energy through space as well as medium. </u>In an electromagnetic wave, electric field generates magnetic field and magnetic field generates electric field. Electric field and magnetic field are perpendicular to each other and to the direction of motion.

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When you heat something of cool it down you don't change the substance you might change the why is looks, but it is still the same substance. For example you cool water to 0 degrees Celsius it turns into ice but it still is two parts hydrogen and one part oxygen H2O. Physical changes will change state and/or form but it will still be what it originally was on the molecular level. Hope that helped. 
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3 years ago
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Part A
jok3333 [9.3K]

Answer:

Using 3 periods to get an accurate reading:

3T = (6.40 S - 0.90 s) = 5.50 S So, T = 1.83 s

m = 0.250 kg

Using algebra:

k= \frac{4\pi ^{2}m }{T^{2} }=\frac{4\pi ^{2}0.250 }{1.90^{2} }=2.95kg/sec

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2 years ago
In the Bohr model of the hydrogen atom, an electron({rm mass};m=9.1; times 10^{ - 31;}{rm kg}) orbits a proton at a distance of
max2010maxim [7]

Answer:

n=6.56×10¹⁵Hz

Explanation:

Given Data

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

To find

Revolutions per second

Solution

Let F be the force of attraction

let n  be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by

F=mω²r......................where ω=2π  n

F=m4π²n²r...............eq(i)

as the values given where

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

we have to find n from eq(i)

n²=F/(m4π²r)

n^{2} =\frac{8.2*10^{-8} }{9.11*10^{-31}* 4\pi^{2} *5.3*10^{-11}  }\\ n^{2}=4.31*10^{31}\\ n=\sqrt{4.31*10^{31}}\\ n=6.56*10^{15}Hz

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3 years ago
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Where,
G = the force of gravity
M1 = the mass of the first object [the mass of the astronaut]
M2 = the mass of the second object [the mass of the planet]
r = the distance between the two objects in metre
F = 6.67 * 10^-11 [66.5 * 8.43 * 10^23] / [4.40 * 10^6]^2
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