if the ball dropped from 12 feet and bounces up 2/3 as high on each successive bounce,what is the height of the fourth bounce?
1 answer:
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This is a Bayes Theorem Problem
P(oil | negative test) P(negative test)= P(negative test | oil) P(oil)
P(oil | negative test) = P(negative test | oil) P(oil) / P(negative test)
P(oil | negative test) =P(negative test | oil) P(oil) / ( P(negative test | oil) P(oil) + P(negative test | no oil) P(no oil) )
We're given the prior probability of oil, P(oil)=.45, so P(no oil)=.55
We given P(negative test | no oil) = 0.80, so P(negative test | oil) = .20
Choice A
We have the next the next division
And we need to use synthetic division to find the quotient.
1. we must write the problem in a division-like format.
- we need to take the constant term of the divisor with the opposite sign and write it to the left. Then, we must write the coefficients of the dividend to the right.
2. we must write down the first coefficient without changes:
3. we need to multiply the entry in the left part of the table by the last entry in the result row and add the obtained result to the next coefficient of the dividend, and write down the sum.
4. We must continue the same process
5. We must continue the same process
Now, We have completed the table and have obtained the following resulting coefficients: 6. -16, 9 and -24
To identify the quotient we need all coefficients we obtained except the last coefficients which represents the remainder.
So, the quotient would be
ANSWER:
-6x^2-16x+9
