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Vadim26 [7]
3 years ago
7

Suppose M is the midpoint of segment CD, CM = 5x-12 and MD = 2x + 9. What is x?​

Mathematics
1 answer:
olasank [31]3 years ago
8 0

Answer:

use this https://www.calculatorsoup.com/

Step-by-step explanation:

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The answer must be  C
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Two people independently each pick a number from 1 to 10. what is the probability that the two of them pick the same number?
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1 in 10 is the probability of two people picking the same number.
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The distance traveled by a certain vehicle varies directly to the amount of fuel the vehicle consumes. The vehicle traveled 90 m
olga_2 [115]

Answer:

The vehicle covers 126 miles on 7 gallons of fuel.

Step-by-step explanation:

Given:

The distance traveled is directly proportional to the amount of fuel.

For F gallons of fuel distance traveled D miles can be given as:

D ∝ F

D=kF

where k is constant of proportionality.

The vehicle covers D=90 miles on F=5 gallons.

So

90=k(5)

Dividing both sides by 5.

\frac{90}{5}=\frac{k(5)}{5}

18=k

∴ k=18

When F=7 gallons

D=(18)(7)

D=126 miles

∴ The vehicle covers 126 miles on 7 gallons of fuel.

4 0
2 years ago
Michelle has to find the decimal equivalent of 15 yards. How can she do
kipiarov [429]

Answer:

15.0 yards

Step-by-step explanation:

8 0
3 years ago
Find the exact value of sin(cos^-1(4/5))
boyakko [2]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


Also,

\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}


Square both sides and apply the fundamental trigonometric identity:

\mathsf{(5\,cos\,\theta)^2=4^2}\\\\
\mathsf{5^2\,cos^2\,\theta=4^2}\\\\
\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{25\cdot (1-sin^2\,\theta)=16}

\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}


\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}


But \mathsf{0\le \theta\le\pi,} which means \theta lies either in the 1st or the 2nd quadrant. So \mathsf{sin\,\theta} is a positive number:

\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\
\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0
3 years ago
Read 2 more answers
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