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Amanda [17]
3 years ago
5

Translate each phrase to an algebraic expression. (a) the product of 7 and d, decreased by 16 (b) the product of 7 and d decreas

ed by 16
Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

<h2><em><u>a) 7d - 16</u></em></h2><h2><em><u>b) 7(d - 16)</u></em></h2>

Step-by-step explanation:

Question A:

Step 1. The product of 7 and d is = 7d.

Step 2. Then the next part is separated by a comma.

Step 3. This leads to the influence of the idea that 7d is subtracted by 16.

<em><u>Step 4. This concludes that the answer is 7d - 16.</u></em>

Question B:

Step 1: The product of 7 concludes that 7 is alone.

Step 2: The separation of and shows that the part after and is together.

Step 3: If it is together, we can conclude it goes in parentheses.

Step 4: If it is in parentheses, it means the number 7 is being distributed.

<em><u>Step 5: This concludes the answer is 7(d - 16).</u></em>

<em><u></u></em>

Hope this helped,

Kavitha

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At the candy store there are 420 gumdrops and 280 chocolate bars, for a total of 700 candies all together. What is the ratio of
Mekhanik [1.2K]

Answer:

5 : 2

Step-by-step explanation:

Given that:

Number of gumdrops = 420

Number of chocolate bars = 280

Total Number of candies = 700

To find:

The ratio of candies to chocolate bars = ?

Solution:

First of all, let us discuss the method to find the ratio of any two quantities.

Suppose, we need to find the ratio of two numbers p and q.

Then to find the ratio p:q , we need to divide p by q and represent it in the simplest form \frac{a}{b} such that a and b can not be divided further.

Here, to find the ratio of candies to chocolate bar:

Ratio = \dfrac{\text{Number of candies}}{\text{Number of chocolate bars}}\\\Rightarrow \dfrac{700}{280}

Here, we can simplify the fraction by dividing the numerator and denominator by 10 first:

\dfrac{70}{28}

Now, let us divide the numerator and denominator by 14:

\dfrac{5}{2}

So, the ratio is <em>5 : 2</em>

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3 years ago
Please help me on this
Marrrta [24]
It's C x5 the correct answer I'm not sure
3 0
3 years ago
(2b) A rectangular prism measures 2 &amp; 2/5 inches by 3 &amp; 1/5 inches by 2 inches. How many cubes with edge length 1/5 inch
erastova [34]

Answer:

1920 cubes.

Step-by-step explanation

Turn both the mix numbers into improper fractions.

2 2/5 = 12/5

3 1/5 = 16/5

Then you will turn 1/5 into its reciprocal and multiply both the improper fractions by it. You can just casually multiply 2 and 5.

12/5 * 5/1 = 12

16/5 * 5/1 = 16

2 * 5 = 10

Next you multiply all together to get 1920 cubes.

(I could be missing a step. I apologize if I did.)

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Answer:

Step-by-step explanation:

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Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
saw5 [17]

Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

__

The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define <em>a singular triangle</em>. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

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