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dedylja [7]
3 years ago
7

Please help! (Number 15)

Mathematics
2 answers:
Brrunno [24]3 years ago
6 0
Lateral, means 'side'. So basically they want us to find out the surface area of the can, excluding the top and the bottom.

To solve for the lateral surface area, we multiply the height of the paint can by the circumference of the top circle. We know the height is 7 1/2 in but we need to solve for the circumference.

C=πd
C=6 5/8π in

Surface Area=7 1/2*6 5/8π=49 11/16π in² or 156.097in²

Answer= 49 11/16π in² or 156.097in²

vichka [17]3 years ago
4 0
First you find the radius. Pi r squared. Then you multiply the radius by the height
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Solve the equation x³ − 5 = 59
In-s [12.5K]

Answer:

4 = x

Step-by-step explanation:

x³ - 5 = 59     Add five to both sides of the equation.

x³ = 64          Now find the cubed root of 64

∛64 = 4

x = 4

3 0
3 years ago
Does anyone know the answer for the question below.
8090 [49]

Answer: option C

Step-by-step explanation:

The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC

Assuming the given angle is #,

Recalling the trigonometric ratio,

tan # = opposite / adjacent

If tan # = 4, it means

opposite / adjacent = 4/1

Therefore, opposite = 4 and adjacent = 1

Applying Pythagoras theorem,

Hypotenuse^2 = opposite ^2 + adjacent ^2

Hypotenuse = AC

Opposite = 4

Adjacent = 1

AC^2 = 4^2 + 1^2 = 17

AC = ± √17

To determine cos #, we would apply another trigonometric ratio,

Cos# = adjacent /hypotenuse

Cos# = 1/±√17

Cos # =-1 /√17 or 1/√17

8 0
3 years ago
A sledgehammer weighs 18 pounds on Earth and 4 pounds on the planet Namar. 
Advocard [28]
It would weight 18lbs i believe

8 0
3 years ago
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What is the area of a square with the length of a side equaling 3a^5???
Novay_Z [31]

Answer:


Step-by-step explanation:

Yes it is

5 0
3 years ago
Solve for q.<br><br> s = 4p + 4q solve the equation
Harlamova29_29 [7]

Answer:

q = \frac{s -4p}{4}\\

Step-by-step explanation:

s = 4p +4q \\ 4p +4q = s \\ 4p +4q -4p = s -4p \\ 4q = s - 4p \\ \frac{4q}{4} = \frac{s -4p}{4} \\ q = \frac{s -4p}{4}

4 0
3 years ago
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