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Afina-wow [57]
3 years ago
9

A rectangle is 2/5 in. long and 1/3 in. wide. What is the area of the rectangle? Enter your answer in the box as a fraction in s

implest form.
Mathematics
1 answer:
MrRissso [65]3 years ago
3 0
Funny I just answered the same exact question just a minute ago, but anyway the area formula is A=L*W, so that means that you need to multiply 2/5 times 1/3 to get the area. Once you do that it wants you to put it in the simplest form, which only means to reduce it down, unless it doesn't need too. Like if I got 10/20, the simplest form would be 1/2, because 10/20 is the same as 1/2, just reduced down. Apply the same logic to your problem and you will get your answer
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Inverse relations and functions quiz
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Answer:

what are you asking?

Step-by-step explanation:

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Find the slope of the line y = 1/6x + 3/2
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Answer: 1/6

Step-by-step explanation:

Slope is the m in y=mx+b

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How do you divide (n^2-n-29)/(n-6) ??
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9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Polynomial long division is done the way any long division is done. Find a "partial quotient", subtract from the dividend the product of that partial quotient and the divisor. The result is a new dividend. Repeat until the degree of the dividend is less than that of the divisor.

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In the attached, the "Hints" show you how the partial quotient is found, and they show you how the product of the partial quotient and divisor is found.

The partial quotient term is simply the ratio of the highest degree terms of dividend and divisor. (Unlike numerical long division, there is no guessing.)

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The remainder is the dividend of lower degree than the divisor. As in numerical long division, the full quotient expresses the remainder over the divisor.

For example, 5 ÷ 3 = 1 r 2 = 1 + 2/3.

Your full quotient is (n+5) +1/(n-6).

5 0
3 years ago
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8 0
3 years ago
Find the tangent line approximation for 10+x−−−−−√ near x=0. Do not approximate any of the values in your formula when entering
Svetllana [295]

Answer:

L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x

Step-by-step explanation:

We are asked to find the tangent line approximation for f(x)=\sqrt{10+x} near x=0.

We will use linear approximation formula for a tangent line L(x) of a function f(x) at x=a to solve our given problem.

L(x)=f(a)+f'(a)(x-a)

Let us find value of function at x=0 as:

f(0)=\sqrt{10+x}=\sqrt{10+0}=\sqrt{10}

Now, we will find derivative of given function as:

f(x)=\sqrt{10+x}=(10+x)^{\frac{1}{2}}

f'(x)=\frac{d}{dx}((10+x)^{\frac{1}{2}})\cdot \frac{d}{dx}(10+x)

f'(x)=\frac{1}{2}(10+x)^{-\frac{1}{2}}\cdot 1

f'(x)=\frac{1}{2\sqrt{10+x}}

Let us find derivative at x=0

f'(0)=\frac{1}{2\sqrt{10+0}}=\frac{1}{2\sqrt{10}}

Upon substituting our given values in linear approximation formula, we will get:

L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}(x-0)  

L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}x-0

L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x

Therefore, our required tangent line for approximation would be L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x.

8 0
3 years ago
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