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3 years ago

brainliest goes to whoever answers the question correctly also if you want more points answer my other questions

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

A and B are functions

Step-by-step explanation:

for A, none of the x's repeat which makes it a FUNCTION

for B, when it starts with x^2, it will always be a FUNCTION (its a quadratic)

for C, 10 repeats for the x so it is NOT A FUNCTION

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3 100° B. 48 270 o ZA= degrees b= (=

solong [7]

Answer:

Angle A = 53

Step-by-step explanation:

All triangles add up to 180 so...

Lets use x to describe angle A

100+27+x=180

127+x=180

x=53

I'm confused what its asking about b and c but hope this helps a bit :)

6 0

3 years ago

Find the unit rate. 48 cupcakes in 6 boxes=cupcakes per box

natka813 [3]

Answer: 8 cupcakes per box

Step-by-step explanation: "Per box" means in 1 box, so we can rewrite the given statement using fractions as

48 cupcakes/6 boxes = __ cupcakes/1 box.

To find out what goes in the blank, notice that we

have a 1 in the denominator of our second fraction.

So we want to find a fraction that is equivalent

to 48/6 that has a 1 in the denominator.

If we divide the numerator and denominator of 48/6 by 6,

we get the equivalent fraction 8/1 or 8 cupcakes/1 box.

So now we have 8 cupcakes/1 box = __cupcakes/1 box.

So an 8 must go in the blank which means that the unit rate

for 48 cupcakes in 6 boxes is 8 cupcakes per box.

6 0

3 years ago

Read 2 more answers

Calculate the area of area of a rectangular with a base of 10cm and a height of 6cm

nadya68 [22]

Answer:

60cm²

Step-by-step explanation:

Length = 6cm

Breadth = 10cm

Area of rectangle = l×b

=( 10 ×6)cm

= 60cm²

Hope it helps.

8 0

3 years ago

Read 2 more answers

Of the numbers 8, 9, or 10 which is a solution of the inequality n - 3 > 6

leva [86]

Answer:

10, because 10-3 is 7, and 7 is greater than 6.

3 0

3 years ago

Read 2 more answers

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

$\text{Minimum value }= 53$

$Q_1=62$

$Median=80$

$Q_3=86$

$\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

For second box plot

$\text{Minimum value }= 56$

$Q_1=62$

$Median=74$

$Q_3=89$

$\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value. It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range. It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

5 0

3 years ago