All categories

2 years ago

.. pls help me....!!!!! Determine whether the point (-2,4) satisfy y<3x+5,y=3x+5 or y >3x+5..

Mathematics

1 answer:

nasty-shy [4]2 years ago

7 0

Answer:

$y > 3\cdot x + 5$

Step-by-step explanation:

Let $A(x,y) = (-2,4)$ and $y = 3\cdot x + 5$ . Now we evaluate the given function at $x = -2$ :

$y = 3\cdot x + 5$ (1)

$y = 3\cdot (-2)+5$

$y = -6 +5$

$y = -1$

Which means that $y$ is less than the y-component of A. Therefore, the right answer is $y > 3\cdot x + 5$ .

You might be interested in

Place labels on the coordinate plane below.

Nuetrik [128]

Answer:

the x-axis is the middle horizontal line

the y-axis in the middle vertical line

the origin is (0,0) or where the x and y-axis cross

in the upper left quadrant the x-axis is negative and the y-axis is positive.

in the upper right quadrant the x-axis is positive and so is the y.

in the lower left quadrant both the x and y-axis is negative.

in the lower right quadrant the x-axis is positive and the y-axis is negative.

8 0

2 years ago

Read 2 more answers

If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

Where can the perpendicular bisectors of an acute triangle intersect

ololo11 [35]

I think inside the triangle......

4 0

3 years ago

1) Determine the length of "x" in the following triangle and mention if you're solving

Aliun [14]

Answer:

X=48

Step-by-step explanation:

x^2+y^2=z^2

but in this case it's z^2-y^2=x^2

so 73^2= 5329

and 55^2=3025

5329-3025=2304

Square Root of 2304 is 48, meaning X=48

Hope this helps!

3 0

2 years ago

7x-y=19 2x-3y=19 solve by elimination

avanturin [10]

Answer:

x=2 y=-5

Step-by-step explanation:

7x-y=19

2x-3y=19

Multiply the first equation by -3

-3(7x-y)=19*-3

-21x +3y =-57

Add this to the second equation to eliminate y

-21x +3y =-57

2x-3y=19

-----------------------

-19x = -38

Divide by -19

-19x/-19 = -38/-19

x = 2

Now we need to find y

7x-y = 19

7(2) -y =19

14 -y =19

Subtract 14 from each side

14-14 -y=19-14

-y=5

Multiply by -1

y = -5

8 0

3 years ago

.. pls help me....!!!!! Determine whether the point (-2,4) satisfy y<3x+5,y=3x+5 or y >3x+5..​

.. pls help me....!!!!! Determine whether the point (-2,4) satisfy y<3x+5,y=3x+5 or y >3x+5..